On Mon, Jan 10, 2022 at 8:20 PM Raul Miller wrote:
> Hmm...
>
> I like your use of reference rotations R. And, your approach to
> combining what were a bunch of different steps in mine looks nice. (It
> takes a bit longer this way, but for this puzzle the extra time I
> needed to code up my appro
For Henry I expect: as I share code between J903 on the laptop and J701 on this
iPad, I’ve been avoiding the use of {{ }} objects. (My iPad can’t support
Ian’s new J902.)
But I was just wondering about adding a routine to the J701 start.ijs script to
parse a J903 script translating direct def
If you avoid nested {{ }} blocks, 5!:5 would do this.
In other words, this works:
mean=: {{ (+/ % #) y}}
5!:5<'mean'
3 : '(+/ % #) y'
But this would be useless for your purposes:
mean=: {{ {{x + y}} {{u/}} {{x % y}} {{#y}} }}
5!:5<'mean'
3 : '{{ x + y }} {{ u/ }} {{ x % y }} {{ #
There is nothing I know of that does what {{ }} does. But Raul's idea
is pretty close. As he notes, it fails for nested {{ }} (there is much
code that expects the result of 5!:5 <'explicitname' to have the form m
: string, but nested {{ }} seemed OK).
Henry Rich
On 1/11/2022 9:19 AM, Raul M
Oh well. I thought you might have test-bedded these forms in J before moving
to C, Henry, in which case there might have been a readymade J script!
As for Raul’s suggestion, that’s fine, but, in as far as I have copied across
to J701, just typing the verb’s name in the session reveals the n
Hi Mike,
You may not know, but there is a new J app that Ian Clark has developed called
J901 (although it is running a version of J903 I believe) that supports {{ }}
You can find it in the app store for the iPad or the iPhone. The interface is
slightly different, but it is really good.
Cheers,
I think it's easier to post my code than to try answering your question.
I've run successfully this in a new session, so I think it's
self-contained.
Apologies for the verbose code - it's as I wrote it, and I haven't
attempted
to polish it for presentation here. The function "part2" , not s
Thanks, Bob - yes, I do know. Ian gave up hoping to keep J901
compatible with my iOS 11, later iOS 12.
My iPad is too old to support the later versions of iOS which support
his J901 app. Liz (my email
address's other half!) does have it on her iPad, but I don't want to
take over her tablet!
Hi,
I sometimes time expressions with a left argument of something like 10 or
100, e.g. "(100) 6!:2 'singlePair testSP0'". This gives me an average time
for the multiple iterations. It would be nice to be able to get the
standard deviation of the multiple invocations as well.
I can do this myse
Your approach seems good. You can also do:
(i.10) timex '+/i.1'
Regarding the domain of timing code,
I'd be surprised, and so curious, if the standard deviation wasn't a "fixed
percentage" of average time, with a bias for quickest functions having the
highest standard dev as a percentage
Thanks for the tip - it's a cleaner way to accomplish what I want.
I'm not sure about your standard deviation supposition or maybe I don't
understand what you're saying.
I think you can get arbitrarily large standard deviations by supplying
arguments with large standard deviations, e.g.
usus #
Thanks Raul for all great hints (not all yet absorbed by me, for example
the usage of {{ }}, but will in time, when it becomes clear to me why it is
better).
For the record. I have documented all ways suggested in this thread to have
always at my disposal:
https://github.com/paweljakubas/j-random-
Ah, gotcha -- thanks!
--
Raul
On Tue, Jan 11, 2022 at 11:23 AM 'Michael Day' via Programming
wrote:
>
> I think it's easier to post my code than to try answering your question.
> I've run successfully this in a new session, so I think it's
> self-contained.
>
> Apologies for the verbose code -
{{ }} is just a convenience.
I like it because I do not have to concern myself with doubling quotes
when using the expressions in string contexts.
Thanks,
--
Raul
On Tue, Jan 11, 2022 at 3:45 PM Pawel Jakubas wrote:
>
> Thanks Raul for all great hints (not all yet absorbed by me, for example
https://adventofcode.com/2021/day/22
The day 22 puzzle was about "rebooting the reactor".
Here, we have a sequence of steps which consist of turning on, or off,
a rectangular cuboid in our coordinate system. In this puzzle each
x,y,z coordinate value was referred to as a cube.
s=: sample=:{{)n
o
Briefly for now, as the pub quiz went on far too long & it’s midnight...
I hope my hint wasn’t too much of a spoiler; unintended if it was.
My insight was somewhat mathematical, and is similar in a way to the Moebius
transform. I worked through a 2-d analogue looking at intersecting rectangles
Huh... well...
I suspect you are talking more about
https://en.wikipedia.org/wiki/M%C3%B6bius_inversion_formula than about
https://en.wikipedia.org/wiki/M%C3%B6bius_transformation
And, maybe specifically
https://en.wikipedia.org/wiki/Inclusion%E2%80%93exclusion_principle
That said, I'm not yet s
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