typically when I build forms like that I have a database that is giving me
all the data so I only have to update the loop once for all the checkboxes
:-)
but yes you can use the $$() Selector method to use the names - I think you
have to do it this way though
$$(input[name='kitcat[]']:checked)
// this works with names that contain spaces and arrays[]...
Validation.add('validate-one-array', 'Error message text', function(value,
element) {
var elmName = input:checkbox[name=' +element.name +'];
var bChecked = false; // not validated
$$(elmName).each(function(elm) {
if(
Prototype has a method for what you are trying called any()
http://api.prototypejs.org/language/Enumerable/prototype/any/
you create an iterator function and pass it to any
var elmName = input:checkbox[name=' +element.name +'];
var bChecked = false; // not validated
var anychecked
Ha! I knew there had to be a shorter way to do this!
Thanks!
On Mon, Apr 1, 2013 at 3:53 PM, Jason Westbrook jwestbr...@gmail.comwrote:
Prototype has a method for what you are trying called any()
http://api.prototypejs.org/language/Enumerable/prototype/any/
you create an iterator
Happy Easter!
I have an array of checkboxes on a form (about 15 of them) arranged in rows
like this:
trtdinput type='checkbox' name='kitcat[]'
.../tdtdname/tdtddescription/td/tr
What I have been trying to use is this:
$(input:checkbox[name=kitcat]:checked).each(function() {
// if one is
Try adding a separate class to all of your checkboxes that are in the group
and then do this
if( $$('.groupchecks:checked').length == 0 )
{
//no checked checkboxes
{
Jason Westbrook | T: 313-799-3770 | jwestbr...@gmail.com
On Sun, Mar 31, 2013 at 8:30 AM, Phil Petree phil.pet...@gmail.com
try
$$(...)
because $() equal document.getElementById
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Hey Jason... I guess the rest of the group are all slugs! How dare they
take Easer off! LOL
I had kinda come to the same conclusion... what I implemented was:
if($$('input:checked').length 0)
return true;
This kind of works because the ONLY input on this page are checkboxes
(think
