ely
> tuned for PyPy and so you don't get best performance and results may be
> unstable.
>
> Victor
>
> Le 16 avr. 2017 23:05, "Frank Wang" a écrit :
>
>> Hi,
>>
>> I was wondering if there were a "standard" set of PyPy benc
Hi,
I want to modify the definition of socket.socket() to include an extra
parameter. I found this function (newsocket):
https://bitbucket.org/pypy/pypy/src/8175c5e20480b2c8e1b95c7f758458db7193f1a8/pypy/module/_socket/interp_socket.py?at=default&fileviewer=file-view-default#interp_socket.py-613
Hi,
I was wondering if there were a "standard" set of PyPy benchmarks that are
commonly used.
I'm currently using this: http://pyperformance.readthedocs.io/
Thanks,
Frank
___
pypy-dev mailing list
pypy-dev@python.org
https://mail.python.org/mailman/lis
Hi,
I made some modifications to pypy, but the new pypy-c binary results in a
segfault on certain instructions. What's the easiest way to do a traceback
to see what led to the segfault?
Thanks,
Frank
___
pypy-dev mailing list
pypy-dev@python.org
https:/
Hi,
I'm trying to figure out the opcodes that the "append" function calls for
arrays. When I use the dis tool, it just says that it looks up a method
"append" using the LOOKUP_METHOD opcode. Is there a tool that allows me to
disassemble built-in functions like "append", or what the best way to do
lled by an
application.
Thanks,
Frank
On Fri, Jan 27, 2017 at 12:40 PM, Frank Wang wrote:
> Hi Carl,
>
> Thanks for the information! I just have to do it for a specific attribute.
> It is just a bit tedious as you said, making sure the semantics of the
> parameter type and result
do this for absolutely *every*
> interpreter level attribute, there may be a way to achieve this effect
> with some magic meta-programming, though I'd have to think a bit how.
>
> Cheers,
>
> Carl Friedrich
>
> On 27/01/17 16:45, Frank Wang wrote:
> > Hi,
> >
Hi,
At the application level, I want to modify some interpreter-level
attributes of an object. Right now, I have the interpreter level functions
that allow me to modify the interpreter object. Is the easiest way to have
an application access interpreter level attributes to use a Mixed Module
with
Hi,
When I compile PyPy in the "goal" folder, I compile it with the following
options:
pypy ../../rpython/bin/rpython --opt=2
Is this the proper way to compile pypy without JIT, or am I doing something
wrong?
Thanks,
Frank
___
pypy-dev mailing list
py
Hi Armin,
Thanks for the help! It seems like the problem is that somewhere in my
code, I called .set_rbflags(x), and it's not checked that x is a dict.
Frank
On Fri, Jan 13, 2017 at 6:36 AM, Armin Rigo wrote:
> Re-hi,
>
> On 13 January 2017 at 12:34, Armin Rigo wrote:
> > says: you are stor
3:00 PM, William ML Leslie <
william.leslie@gmail.com> wrote:
> On 12 January 2017 at 09:08, Frank Wang wrote:
> > def binaryoperation(operationname):
> > """NOT_RPYTHON"""
> > def opimpl(self, *ignored):
> > operat
v944 = newdict()
v945 = setattr(self_268, ('rb_flags'), v944)
--end--
Any thoughts on this?
Frank
On Mon, Dec 19, 2016 at 10:32 PM, Frank Wang wrote:
> Hi Armin,
>
> It seems that with your suggestions, things have started to work!
>
> Thanks again for the help
Hi Armin,
It seems that with your suggestions, things have started to work!
Thanks again for the help!
On Mon, Dec 19, 2016 at 5:57 PM Armin Rigo wrote:
> Hi Frank,
>
> On 20 December 2016 at 01:29, Frank Wang wrote:
> > This also seems to happen in a lot of classes becaus
but only for
> RPython.
>
> Cheers,
>
> Carl Friedrich
>
> On December 19, 2016 5:42:12 PM GMT+01:00, Frank Wang
> wrote:
>>
>> Hi Armin,
>>
>> If I modify the line to __slots__ = ('__weakref__', 'rb_flags',), I get
>> the f
This also seems to happen in a lot of classes because W_Root is the parent
class for many classes. Is there a way to universally turn off this
immutable flag (assuming it's okay) in all classes?
Frank
On Mon, Dec 19, 2016 at 3:55 PM, Frank Wang wrote:
> Hi Carl,
>
> Thanks for
, ('w_dict'))
w_value_0 = simple_call(v0, v1, name_0)
v2 = getattr(self_0, ('lazy'))
v3 = bool(v2)
--end--
I wonder what error in your opinion is easier to get around.
Thanks for the help!
Frank
On Mon, Dec 19, 2016 at 2:26 AM, Armin Rigo wrote:
> H
>
> Yes, you'll get an instance variable that way.
>
> Cheers,
>
> Carl Friedrich
>
> On December 16, 2016 6:05:56 PM GMT+01:00, Frank Wang
> wrote:
>
>> Hi Armin,
>>
>> Thanks for the suggestion! I'll see if that works. Just t
gt;
> On 15 December 2016 at 21:06, Frank Wang wrote:
> > Right now, I know W_Root has no __init__ function, and when I try to add
> > one. I run into all sorts of problems because TypeDef calls
> W_Root.__new__
> > with some parameters, but "new" function seems to be c
Hi,
I don't know if this is the proper list to ask this question.
I am trying to add a dictionary to W_Root. The reason for this is that I
want all interpreter objects to contain this dictionary. This is for a
research project to implement some form of information flow control in PyPy.
Right now
19 matches
Mail list logo
