Chetan Palliwal added the comment:
If the index() is working fine. why my previous attached code sample is
returning 0 for each time I try to get the index for element 11 in the list.
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Python tracker
<https://bugs.python.org/issue42
Chetan Palliwal added the comment:
can you let it work using the index method then it index() is working fine. I
can resolve it by using enumerate and another way.
The issue I raised here for the index() method not for enumerate.
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status: closed -> o
Chetan Palliwal added the comment:
if an element in the list present more than 1 times in different order and we
try to get the index of it python 3.6 is returning only the first index value
for all places of that element in that list.
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Added file: https://bugs.python.org
New submission from Chetan Palliwal :
In [1]: po=[11,22,33,44,11,55,66,11,88]
In [2]: for lm in po:
...: if lm==11:
...: print("value is = {} and index is = {}".format(lm,po.index(lm)))
...: else:
...: print("value is = {} and index is
