New submission from Luke Schubert: If the following function is saved in listcomp.py:
def encode(inputLetters): code = {'C':'D', 'F':'E'} return set(code[x] for x in inputLetters) and the following code is used to create a symtable for this function: import symtable if __name__ == "__main__": fileName = 'listcomp.py' f = open(fileName, 'r') source = f.read() table = symtable.symtable(source, fileName, 'exec') children = table.get_children() for childTable in children: symbols = childTable.get_symbols() for s in symbols: if (not s.is_referenced()): print ("Unused symbol '%s' in function '%s'" % (s.get_name(), childTable.get_name())) then is_referenced() returns false for the 'code' symbol. If the following function is saved instead: def encode2(inputLetters): code = {'C':'D', 'F':'E'} return [ code[x] for x in inputLetters ] then is_referenced() returns true for the 'code' symbol. Possibly I'm misunderstanding what is_referenced() means, but I thought it should return true in both cases? ---------- messages: 259316 nosy: luke.schubert priority: normal severity: normal status: open title: symtable.Symbol.is_referenced() returns false for valid use versions: Python 2.7 _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue26255> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com