[issue34226] cgi.parse_multipart() requires undocumented CONTENT-LENGTH in Python 3.7

2020-06-12 Thread Niklas Sombert
Niklas Sombert added the comment: Since there's the easy workaround of just setting pdict["CONTENT-LENGTH"] I personally don't have a problem with this staying the way it is. But it would be really nice if this were

[issue34226] cgi.parse_multipart() requires undocumented CONTENT-LENGTH in Python 3.7

2019-09-03 Thread Niklas Sombert
Change by Niklas Sombert : -- nosy: +ytvwld ___ Python tracker <https://bugs.python.org/issue34226> ___ ___ Python-bugs-list mailing list Unsubscribe:

[issue34628] urllib.request.urlopen fails when userinfo is present in URL

2018-11-10 Thread Niklas Sombert
Niklas Sombert added the comment: This behaviour would be better than the current one, yes. -- ___ Python tracker <https://bugs.python.org/issue34628> ___ ___

[issue34628] urllib.request.urlopen fails when userinfo is present in URL

2018-11-09 Thread Niklas Sombert
Niklas Sombert added the comment: Another month has passed, just saying. -- ___ Python tracker <https://bugs.python.org/issue34628> ___ ___ Python-bugs-list m

[issue34628] urllib.request.urlopen fails when userinfo is present in URL

2018-10-05 Thread Niklas Sombert
Niklas Sombert added the comment: Hey, this is almost a month old. (Not a problem, really. But I thought, I should bump this.) -- ___ Python tracker <https://bugs.python.org/issue34

[issue34628] urllib.request.urlopen fails when userinfo is present in URL

2018-09-12 Thread Niklas Sombert
Niklas Sombert added the comment: Thank you for your response. But if this is an explicit choice, I would like to have better exceptions: >>> from http.client import HTTPConnection >>> h = HTTPConnection("user:1...@example.net") raises http.client.Invali

[issue34628] urllib.request.urlopen fails when userinfo is present in URL

2018-09-11 Thread Niklas Sombert
New submission from Niklas Sombert : Today I tried to access URLs like this one: http://user:1...@example.net:8080. The result was this: >>> import urllib.request >>> urllib.request.urlopen("http://user:1...@example.net:1234/";) Traceback (most recent call l