[issue26400] SyntaxError when running Python 2.7 interpreter with subprocess.call

giumas added the comment: It worked also for me with the official 64-bit distribution! I get that buggy behavior with the Anaconda distribution (this was the "Library\bin"). I should have checked it as first step! My apologies and thank you so much for your kind help. -- resolution:

[issue26400] SyntaxError when running Python 2.7 interpreter with subprocess.call

Eryk Sun added the comment: Your example worked fine for me with the official 64-bit distribution of 2.7.10 installed in "C:\Program Files\Python27" on Windows 10. I created a junction from "C:\Py27x64" to the 2.7 installation directory in order to run the example as provided. This issue

[issue26400] SyntaxError when running Python 2.7 interpreter with subprocess.call

giumas added the comment: No, I don't. I have just double-checked it. Did you try to run my minimal example on your machine? If yes, are you getting the same behavior? -- ___ Python tracker

[issue26400] SyntaxError when running Python 2.7 interpreter with subprocess.call

Eryk Sun added the comment: The error you're getting indicates that stdin is set to binary mode for some reason. You can see this using the -u command line option: C:\>py -2 -u Python 2.7.10 (default, May 23 2015, 09:44:00) [MSC v.1500 64 bit (AMD64)] on win32 Type "help",

[issue26400] SyntaxError when running Python 2.7 interpreter with subprocess.call

New submission from giumas: On Windows, I am getting a `SyntaxError` when I try to input commands after having launched a Python 2.7.x interpreter with `subprocess.call`. This is a minimal example: import os import subprocess def python_env_path(python_path):