[issue32194] When creating list of dictionaries and updating datetime objects one by one, all values are set to last one of the list.

Gareth Rees added the comment: The behaviour of the * operator (and the associated gotcha) is documented under "Common sequence operations" [1]: Note that items in the sequence s are not copied; they are referenced multiple times. This often haunts new Python

[issue32194] When creating list of dictionaries and updating datetime objects one by one, all values are set to last one of the list.

Dmitry Kazakov added the comment: This is not a bug in Python. Refer to this page for the explanation: https://stackoverflow.com/questions/240178/list-of-lists-changes-reflected-across-sublists-unexpectedly Basically, [{}]*3 creates a list with three references to the

[issue32194] When creating list of dictionaries and updating datetime objects one by one, all values are set to last one of the list.

New submission from Joona Mörsky : When creating list of dictionaries and updating datetime objects one by one, all values are set to last one of the list. Ubuntu Linux 4.10.0-40-generic #44~16.04.1-Ubuntu SMP Thu Nov 9 15:37:44 UTC 2017 x86_64 x86_64 x86_64 GNU/Linux