Steven D'Aprano added the comment:
I'm glad that you fixed the bug in your code, but this is not a bug in
Python. It isn't "a parsing issue", the code is parsed fine. What you
did was no different from:
def func():
print(x)
x = 1
except that the binding operation was an
arts stars added the comment:
It is not for debuging my code. your answer is really middleclass sorry to say
that.
you admit its a due the undefined name of var DiaObjectFactoryHelper
that is exactly I wanted to point out.
I solved my issue not having answer like in the FAQ like you simply
Steven D'Aprano added the comment:
In the future, please remember that this is not a help desk for getting help
with your code, it is for reporting bugs. There are many forums that are happy
to help you understand why your code is not working as you expect (if you are a
beginner to Python, t
Steven D'Aprano added the comment:
This is not a bug, you are trying to print the value of the local variable
DiaObjectFactoryHelper before you have defined the variable.
UnboundLocalError is a subclass of NameError that is used when the undefined
name is a local variable instead of a global
New submission from arts stars :
Hello,
I have this situation:
def test():
if True :
print("Exception"+DiaObjectFactoryHelper)
else:
from . import DiaObjectFactoryHelper
pass
test()
---
it generates instead of (like the
