Steven D'Aprano added the comment:
See also the FAQs:
https://docs.python.org/3/faq/programming.html#why-do-lambdas-defined-in-a-loop-with-different-values-all-return-the-same-result
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nosy: +steven.daprano
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Python tracker
Christian Heimes added the comment:
You are running in a typical scope issue. The local and global scope of a
lambda work differently than you expect. You can work around the issue by
making fun a local variable:
for name, fun in namefun:
name2fun[name] = lambda x, fun=fun: fun(x)
New submission from Vincent Liang :
Strange behavior is found when lambda is used inside for-loop.
code:(same as attached file)
# begin of CODE
def aa(x):
print("aa")
def bb(x):
print("bb")
namefun = [
("a", aa),
("b", bb),
]
name2fun = {}
for name, fun in namefun:
