To pass by reference or by copy of - that is the question from hamlet.
(hamlet - a community of people smaller than a village python3.4-linux64)
xlist = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
i = 0
for x in xlist:
print(xlist)
print(\txlist[%d] = %d % (i, x))
if x%2 == 0 :
On Thu, Aug 6, 2015 at 1:25 AM, John Doe z2...@bk.ru wrote:
To pass by reference or by copy of - that is the question from hamlet.
(hamlet - a community of people smaller than a village python3.4-linux64)
xlist = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
i = 0
for x in xlist:
print(xlist)
The iterator is not revaluated, instead, it is constructing a single
iterator, in this case a list_iterator. The list_iterator looks at the
underyling list to know how to iterate so when you mutate the underlying
list, the list_iterator sees that. This does not mee the expression used to
generate
On Wed, Aug 05, 2015 at 06:25:07PM +0300, John Doe wrote:
To pass by reference or by copy of - that is the question from hamlet.
(hamlet - a community of people smaller than a village python3.4-linux64)
[snip question]
John, you have already posted this same question to the tutor list,
where
