thanks guys,
the solution for me was
python2.4 setup.py install --prefix=/usr/local
cheers, AZ
On Jun 14, 11:00 am, Steven D'Aprano wrote:
> On Mon, 14 Jun 2010 01:30:09 -0700, Alexzive wrote:
> > what to change in order to get "python" calling python 2.4.3 instea
Hello there,
my Mandriva has the 2.6.4 python pre-installed (in /usr/lib64/
python2.6/)
I need to install numpy 1.4 for python 2.4.3 (I installed it
separately from source on/usr/local/lib/python2.4/ )
but still typing "python" I get:
Python 2.6.4 (r264:75706, Jan 8 2010, 18:59:59)
[GCC 4.4.1] o
sorry it was just bullshit what I wrote about the second bottleneck,
it seemed to hang up but it was just me forgetting to double-enter
during debugging after "for cycle".
On May 26, 1:43 pm, Alexzive wrote:
> thank you all for the tips.
> I 'll try them soon.
>
UN = F[f].fieldOutputs['U'].getSubset(region=TOP).values <---
... EPS_nodes[f] = UN[10].data[Scomp-1]/L3
###
unfortunately I don't have time to learn cython. Using dictionaries
sounds promising.
Thanks!
Alex
On May 26, 8:14 am, Stefan Behnel wrote:
> Alexzive, 25.05.201
Hello Pythonguys!
is there a way to improve the performance of the attached code ? it
takes about 5 h on a dual-core (using only one core) when len(V)
~1MIL. V is an array which is supposed to store all the volumes of
tetrahedral elements of a grid whose coord. are stored in NN (accessed
trough th
On Feb 11, 1:08 pm, Tim Chase wrote:
> Alexzive wrote:
> > I am just wondering if there is a quick way to improve this algorithm
> > [N is a structured array which hold info about the nodes n of a finite
> > element mesh, and n is about 300.000). I need to extract info from N
Hello guys,
I am just wondering if there is a quick way to improve this algorithm
[N is a structured array which hold info about the nodes n of a finite
element mesh, and n is about 300.000). I need to extract info from N
and put it in to a 3*n matrix NN which I reshape then with numpy. I
think to
Hello,
I am a newby with python. I wrote the following code to extract a text
from a file and write it to another file:
linestring = open(path, 'r').read() #read all the inp file in
linestring
i=linestring.index("*NODE")
i=linestring.index("E",i)
e=linestring.index("*",i+10)
textN = linestring[i+
Hello,
I have this matrix [20*4 - but it could be n*4 , with n~100,000] in
file "EL_list" like this:
1, 1, 2, 3
2, 4, 1, 5
3, 5, 1, 6
4, 7, 5, 6
5, 8, 7, 9
6, 8, 5, 7
7,
Hello there,
I'd like to get the same result of set() but getting an indexable
object.
How to get this in an efficient way?
Example using set
A = [1, 2, 2 ,2 , 3 ,4]
B= set(A)
B = ([1, 2, 3, 4])
B[2]
TypeError: unindexable object
Many thanks, alex
--
http://mail.python.org/mailman/listinfo/py
Hello there,
let's suppose I have the following matrix:
mat = [[1,2,3], [3,2,4], [7,8,9], [6,2,9]]
where [.. , .. , ..] are the rows.
I am interested into getting the "row index" of all the matrix rows
where a certain number occurs.
For example for 9 I should get 2 and 3 (starting from 0).
For
Hello there :) ,
I am a python newbie and need to run following code for a task in an
external simulation programm called "Abaqus" which makes use of python
to access the mesh (ensamble of nodes with xy coordinates) of a
certain geometrical model.
[IN is the starting input containing the nodes to
12 matches
Mail list logo
