Thanks Peter and 7stud. That is the solution that really works for
me.
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Okay does anyone know how to decorate class member functions?
The following code gives me an error:
Traceback (most recent call last):
File decorators2.py, line 33, in module
s.update()
File decorators2.py, line 13, in __call__
retval = self.fn.__call__(*args,**kws)
TypeError:
Oh I should mention the decorator needs to have some notion of state
(such as with the above class)
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are you sure your variable isn't in some code block that wouldn't be
read on import? Such as:
if __name__ == __main___:
actions = 1
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I just need to keep the state around. I make a call to some function
that is pretty expensive so I want to save it as a member during the
__init__ of the decorator.
Yeah I'm afraid it can't be done either, that's why I asked the group.
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not quite as elegant but here is a workaround... Thanks Virgil for
taking some time to think about it.
---
class Bugger (object):
def __init__ (self, module):
print Entering __init__
self.module = module
self.verb = 0
def instrument (module_name):
def wrapper(f):
On Feb 12, 4:11 pm, Thomas Nelson [EMAIL PROTECTED] wrote:
On Feb 12, 1:35 pm, andrew clarke [EMAIL PROTECTED] wrote:
Thomas, I sent you a message off-list but it bounced due to your mailbox
being full.
Short answer: Subscribe to the [EMAIL PROTECTED] mailing list and
ask your C/C++
try str(p).split()[2]
your class is using the __str__ attribute to print and I am guessing
that is what you are seeing.
Tempo wrote:
Hey. I am trying to grab the prices from the string below but I get a
few errors when I try to do it: Take a look at the code and error
messages below for me
Take your code, pretend it is in file:
$
NAME='ALFA'
CODE='x'
$
a python functions could be:
def change(filename):
fp = open(filename, 'r')
lines = fp.readlines()
fp.close()
for i in range(len(lines)):
if
sweet. I'll definitely be trying to use this.
[EMAIL PROTECTED] wrote:
Just a post to announce some python bindings for picasaweb (photo's
service of google).
--- PycasaWeb (GPL), http://manatlan.infogami.com/pycasaweb
I think it may be usefull for linux users, because it's one of the only
jojoba wrote:
Hello!
Does anyone know how to find the name of a python data type.
Conside a dictionary:
Banana = {}
Then, how do i ask python for a string representing the name of the
above dictionary (i.e. 'Banana')?
thanks to anyone who has time to answer this nube question!
jojoba
can
think of plenty of reasons it would fail, but it really depends on the
app.
Fredrik Lundh wrote:
Andy Terrel wrote:
for i in dir():
if eval(i) == Banana:
print i
(sound of head hitting desk)
/F
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Georg Brandl wrote:
Andy Terrel wrote:
Why bang your head?
Because there's no chance that the original request is sane.
If you want your objects to know their name, give them a name as an attribute.
This is true but sometimes it is just fun to hack around.
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If you did want a linux version you could just make people send a
KeyboardInterupt.
try:
print Press ^C to stop
loop
except KeyboardInterrupt:
some stop action or just pass
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