Changes by Daniel Evers derm...@googlemail.com:
Removed file: http://bugs.python.org/file17065/backlog0.diff
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Changes by Daniel Evers derm...@googlemail.com:
Removed file: http://bugs.python.org/file17066/backlog0_incl_doc.diff
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Changes by Daniel Evers derm...@googlemail.com:
Removed file: http://bugs.python.org/file17067/socket_listen.patch
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Changes by Daniel Evers derm...@googlemail.com:
Removed file: http://bugs.python.org/file21851/server.py
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Changes by Daniel Evers derm...@googlemail.com:
Removed file: http://bugs.python.org/file21852/client.py
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Changes by Daniel Evers derm...@googlemail.com:
Removed file: http://bugs.python.org/file21879/backlog0_complete.patch
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Daniel Evers derm...@googlemail.com added the comment:
Thanks, I removed the old patches and changed the unit test according to your
suggestion.
I kept the usually 5 remark, because I'm not sure how reality really looks
like. But feel free to suggest a patch ;)
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Added file: http
Daniel Evers derm...@googlemail.com added the comment:
Thanks for the tip. I added the unit test and uploaded my final patch (which
includes all changes).
Is it ok to remove the files I uploaded previously?
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Added file: http://bugs.python.org/file21879/backlog0_complete.patch
Daniel Evers derm...@googlemail.com added the comment:
To revive this issue, I tried to write a unit test to verify the behaviour.
Onfurtunately, the test doesn't work and I don't understand why. I hope,
someone here is more enlightend than me...
(files: server.py, client.py)
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Added
Daniel Evers derm...@googlemail.com added the comment:
(client.py)
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Added file: http://bugs.python.org/file21852/client.py
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Daniel Evers derm...@googlemail.com added the comment:
I attached a patch:
The backlog is set to at least 0 instead of 1. I also added a comment that a
backlog 0 can lead to problems and doesn't make sense anyway (so if there are
systems that may crash with backlog 0 this will be avoided
Daniel Evers derm...@googlemail.com added the comment:
Ah right ;)
Sorry, attached the path incl. the doc string.
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Added file: http://bugs.python.org/file17066/backlog0_incl_doc.diff
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Daniel Evers derm...@googlemail.com added the comment:
A second patch for the documentation of socket.listen().
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Added file: http://bugs.python.org/file17067/socket_listen.patch
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New submission from Daniel Evers derm...@googlemail.com:
I'm trying to rewrite a server application in python that accepts exactly 1
connection. I have a previous version written in C that can call listen() on a
socket with a backlog of 0 connections, but this is not possible in python
Daniel Evers derm...@googlemail.com added the comment:
Thanks for your help. I'll close the listen socket.
Nevertheless I'd like to understand the check in sock_listen. The commit
message is not very helpful, I agree, that's why I wrote this issue. 0 is a
valid value, and I'd suggest two ways
Richard Brodie wrote:
subscriptable: supports an indexing operator, like a list does.
Right. You can check this e.g. with
hasattr(x, __getitem__)
because the __getitem__ method is used for indexing.
Daniel
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Peter Otten wrote:
You should ditch what follows and instead add just
def __iter__(self):
return iter(self.__keys)
Mhh. I should start learning the builtins ... :)
To see the problem with your original code (an object serving as its own
iterator) try the
Hi!
Never would have thought of this...
I mixed this with the class-version and created a new class derived from
str for easier printing and added an iterator:
---
class Enum:
class Type(str):
def __init__(self, name):
self.__name = name
Hi!
The sys module provides some useful information, e.g.:
builtin_module_names -- tuple of module names built into this interpreter
version -- the version of this interpreter as a string
version_info -- version information as a tuple
hexversion -- version information encoded as a single integer
Hi!
You can iterate over the internal dictionary:
class Test:
... def __init__(self):
... self.x = 5
... self.y = 6
... self.z = Hallo
...
x = Test()
print x.__dict__
{'y': 6, 'x': 5, 'z': 'Hallo'}
for key, value in x.__dict__.items():
... print
Hi!
Try hex:
hex(120)
'0x78'
Consider converting string - int using the int()-function:
print int.__doc__
int(x[, base]) - integer
Convert a string or number to an integer, if possible. A floating point
argument will be truncated towards zero (this does not include a string
representation of
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