Mark Lawrence於 2014年12月12日星期五UTC+8下午3時17分43秒寫道：
On 12/12/2014 06:22, KK Sasa wrote:
Hi there,
The list comprehension is results = [d2(t[k]) for k in xrange(1000)], where
d2 is a function returning a list, say [x1,x2,x3,x4] for one example. So
results is a list consisting of 1000 lists
Peter Otten於 2014年12月12日星期五UTC+8下午5時13分58秒寫道：
KK Sasa wrote:
Mark Lawrence於 2014年12月12日星期五UTC+8下午3時17分43秒寫道：
On 12/12/2014 06:22, KK Sasa wrote:
Hi there,
The list comprehension is results = [d2(t[k]) for k in xrange(1000)],
where d2 is a function returning a list, say [x1,x2,x3
Jussi Piitulainen於 2014年12月12日星期五UTC+8下午7時12分39秒寫道：
KK Sasa writes:
def p(x,t,point,z,obs):
d = x[0]
tau = [0]+[x[1:point]]
a = x[point:len(x)]
at = sum(i*j for i, j in zip(a, t))
nu = [exp(z[k]*(at-d)-sum(tau[k])) for k in xrange(point)]
de = sum(nu
Peter Otten於 2014年12月12日星期五UTC+8下午8時32分55秒寫道：
Jussi Piitulainen wrote:
KK Sasa writes:
def p(x,t,point,z,obs):
d = x[0]
tau = [0]+[x[1:point]]
a = x[point:len(x)]
at = sum(i*j for i, j in zip(a, t))
nu = [exp(z[k]*(at-d)-sum(tau[k])) for k in xrange(point
Sorry, i should say I'm using pythonxy, maybe it imports other things.
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Hi there,
The list comprehension is results = [d2(t[k]) for k in xrange(1000)], where d2
is a function returning a list, say [x1,x2,x3,x4] for one example. So results
is a list consisting of 1000 lists, each of length four. Here, what I want to
get is the sum of 1000 lists, and then the result
