urllib.url2pathname("http://127.0.0.1:1030/js.cgi?pca&r=12181";)
gives IOError : Bad Url, only coz of the :1030 which should be
accurate portnumber. Is it something I did wrong, or a bug. And what
to do to avoid this (except rewriting url2pathname)?
TIA
Dolf
--
http://mail.python.org/mailman/lis
Think you need a regex like this: regex =
r"\s*instr\s+([0-9]+)\s*(;.*)?"
Then:
import re
test = re.compile(regex)
testing is done as follows:
res = test.match(mystring)
if res:
number = res.group(1) # always a string consisting of decimals
comment = res.group(2) # string starting with ;
I think what you mean is that if you change your list, it is changed
somewhere in your dicrionary to. Lists are always copied as pointers,
except explicitly told other wise. So a = b = [] makes a and be the
same list, and a.append(1) makes b -> [1].
So do something like mydict[mykey] = mylist[:] (
I think that you need a superclass above the M2Crypto one, and change
the open_https method back to the urllibs one.
Moi
Dolf
On Thu, 5 Oct 2006 15:09:22 GMT, Bakker A <[EMAIL PROTECTED]> wrote:
>Hi,
>
>the M2Crypto library overrides the urllib.URLopener.open_https method,
>causing a urllib.urlo
I'm trying to figure out how to get the exact opened url after a
urlopen in urllib2.
Say you have a link : http://myhost/mypath : what do I get back,
- the file mypath on myhost
- the file index.html on myhost/mypath,
- or maybe something else.
Snd what about the following: http;//myhost/index.htm
