Yes i think you can. If you use the struct module. >> import struct >> import math >>y = struct.pack('!f', math.pi) >>print repr(y) '@I\x0f\xdb'
"Michael Yanowitz" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > Hello: > > For some reason I can't figure out how to split > a 4-byte (for instance) float number (such as 3.14159265359) > into its 4-bytes so I can send it via a socket to another > computer. > For integers, it is easy, I can get the 4 bytes by anding like: > byte1 = int_val & 0x000000FF > byte2 = int_val & 0x0000FF00 > byte3 = int_val & 0x00FF0000 > byte4 = int_val & 0xFF000000 > But if I try to do that with floats I get: >>>> pi & 0xFF > Traceback (most recent call last): > File "<stdin>", line 1, in ? > TypeError: unsupported operand type(s) for &: 'float' and 'int' > > Is there some easy way to get what the bytes of the float are? > > Thanks in advance: > Michael Yanowitz > > -- http://mail.python.org/mailman/listinfo/python-list