Bryan Britten wrote:
Hey, gang, I've got a problem here that I'm sure a handful of you will
know how to solve. I've got about 6 *.csv files that I am trying to open;
change the header names (to get rid of spaces); add two new columns, which
are just the results of a string.split() command;
On Wednesday, September 18, 2013 7:12:21 AM UTC+5:30, Bryan Britten wrote:
Hey, gang, I've got a problem here that I'm sure a handful of you will know
how to solve. I've got about 6 *.csv files that I am trying to open; change
the header names (to get rid of spaces); add two new columns,
On 17/9/2013 22:28, Bryan Britten wrote:
Dave -
I can't print the output because there are close to 1,000,000 records. It
would be extremely inefficient and resource intensive to look at every row.
Not if you made a sample directory with about 3 files, each containing
half a dozen lines.
Peter nailed it. Adding in the two lines of code to ensure I was just working
with *.csv files fixed the problem. Thanks to everyone for the help and
suggestions on best practices.
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Hey, gang, I've got a problem here that I'm sure a handful of you will know how
to solve. I've got about 6 *.csv files that I am trying to open; change the
header names (to get rid of spaces); add two new columns, which are just the
results of a string.split() command; drop the column I just
On 17/9/2013 21:42, Bryan Britten wrote:
Hey, gang, I've got a problem here that I'm sure a handful of you will know
how to solve. I've got about 6 *.csv files that I am trying to open; change
the header names (to get rid of spaces); add two new columns, which are just
the results of a
Dave -
I can't print the output because there are close to 1,000,000 records. It would
be extremely inefficient and resource intensive to look at every row. Like I
said, when I take just one file and run the code over the first few records I
get what I'd expect to see. Here's an
