Glen wrote:
#!/usr/local/bin/python
import sys
print 1.\tDo Something
print 2.\tDo Something
print 3.\tDo Something
print 4.\tDo Something
print 5.\tDo Something
print 6.\tExit
choice=raw_input(Please Enter Choice: )
if int(choice)==1:
print Here
else:
pass
if int(choice)==2:
else:
pass
#!/usr/local/bin/python
import sys
print 1.\tDo Something
print 2.\tDo Something
print 3.\tDo Something
print 4.\tDo Something
print 5.\tDo Something
print 6.\tExit
choice=raw_input(Please Enter Choice: )
if int(choice)==1:
print Here
else:
pass
if int(choice)==2:
else:
pass
if
Glen [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED]
if int(choice)==2:
else:
pass
File ./Code.py, line 20
else:
^
IndentationError: expeted an indented block
What am I doing wrong?
As the error trace informs you, Python expexts an indented block. You need
to put something
-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of
Glen
Sent: Tuesday, March 22, 2005 12:44 PM
To: python-list@python.org
Subject: Begniner Question
#!/usr/local/bin/python
import sys
print 1.\tDo Something
print 2.\tDo Something
print 3.\tDo Something
print 4.\tDo Something
print 5
Glen wrote:
#!/usr/local/bin/python
import sys
print 1.\tDo Something
print 2.\tDo Something
print 3.\tDo Something
print 4.\tDo Something
print 5.\tDo Something
print 6.\tExit
choice=raw_input(Please Enter Choice: )
if int(choice)==1:
print Here
else:
pass
if int(choice)==2:
else:
pass
