byte twiddling if the need arouse.
I'm excited already :)
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1E+1 is short hand for a floating point number, not an interger.
float(1E+1)
10.0
You could convert the float to an integer if you wanted (i.e. ceiling,
floor, rounding, truncating, etc.).
Cheers,
Steve
-Original Message-
From: Martin Marcher [mailto:[EMAIL PROTECTED]
Sent: Tuesday,
hmmm
int() does miss some stuff:
1E+1
10.0
int(1E+1)
Traceback (most recent call last):
File stdin, line 1, in module
ValueError: invalid literal for int() with base 10: '1E+1'
I wonder how you parse this?
I honestly thought until right now int() would understand that and
wanted to show
arg, as posted earlier:
int(10.0) fails, it will of course work with float(1E+1) sorry for
the noise...
On Tue, Apr 8, 2008 at 10:32 PM, Martin Marcher [EMAIL PROTECTED] wrote:
hmmm
int() does miss some stuff:
1E+1
10.0
int(1E+1)
Traceback (most recent call last):
File stdin,
Martin Marcher wrote:
hmmm
int() does miss some stuff:
1E+1
10.0
int(1E+1)
Traceback (most recent call last):
File stdin, line 1, in module
ValueError: invalid literal for int() with base 10: '1E+1'
I wonder how you parse this?
I honestly thought until right now int() would
On Sat, 5 Apr 2008 22:02:10 -0700 (PDT), Paddy [EMAIL PROTECTED] wrote:
On Apr 6, 5:18 am, ernie [EMAIL PROTECTED] wrote:
On Apr 6, 10:23 am, Roy Smith [EMAIL PROTECTED] wrote:
int(s) and catching any exception thrown just sounds like the best way.
Another corner case: Is 5.0 an integer or
Jorgen Grahn wrote:
[0] There would have been more if Python had supported hexadecimal
floating-point literals, like (I believe) C does.
C99 does. On the other hand, it isn't a feature I sorely missed during the
first 20 years or so of C's history, but you could always do some creative
byte
which is the best way to check if a string is an number or a char?
could the 2nd example be very expensive timewise if i have to check a
lot of strings?
this
value = raw_input()
try:
value = int(value)
except ValueError:
print value is not an integer
or:
c=raw_input(yo: )
if c in
[EMAIL PROTECTED] wrote:
which is the best way to check if a string is an number or a char?
could the 2nd example be very expensive timewise if i have to check a
lot of strings?
this
value = raw_input()
try:
value = int(value)
except ValueError:
print value is not an integer
or:
On Apr 5, 6:19 pm, [EMAIL PROTECTED] wrote:
which is the best way to check if a string is an number or a char?
could the 2nd example be very expensive timewise if i have to check a
lot of strings?
You might be interested in str.isdigit:
print str.isdigit.__doc__
S.isdigit() - bool
Return
On Apr 6, 9:25 am, Mark Dickinson [EMAIL PROTECTED] wrote:
On Apr 5, 6:19 pm, [EMAIL PROTECTED] wrote:
which is the best way to check if a string is an number or a char?
could the 2nd example be very expensive timewise if i have to check a
lot of strings?
You might be interested in
I always do it the first way. It is simpler, and should be faster.
Ditto. Using int() is best. It's clear, it's correct, and it
should be as fast as it gets.
if c in '0123456789':
print integer
else:
print char
Also, the second way will only work on single-digit numbers
(you
John Machin wrote:
On Apr 6, 9:25 am, Mark Dickinson [EMAIL PROTECTED] wrote:
On Apr 5, 6:19 pm, [EMAIL PROTECTED] wrote:
which is the best way to check if a string is an number or a char?
could the 2nd example be very expensive timewise if i have to check a
lot of strings?
You might be
In article [EMAIL PROTECTED],
Steve Holden [EMAIL PROTECTED] wrote:
This doesn't cater for negative integers.
No, it doesn't, but
s.isdigit() or (s[0] in +- and s[1:].isdigit) # untested
does.
I think this fails on-1. So, then you start doing
s.strip().isdigit(), and then
On Apr 6, 10:23 am, Roy Smith [EMAIL PROTECTED] wrote:
In article [EMAIL PROTECTED],
Steve Holden [EMAIL PROTECTED] wrote:
This doesn't cater for negative integers.
No, it doesn't, but
s.isdigit() or (s[0] in +- and s[1:].isdigit) # untested
does.
I think this fails on-1.
On Apr 6, 5:18 am, ernie [EMAIL PROTECTED] wrote:
On Apr 6, 10:23 am, Roy Smith [EMAIL PROTECTED] wrote:
In article [EMAIL PROTECTED],
Steve Holden [EMAIL PROTECTED] wrote:
This doesn't cater for negative integers.
No, it doesn't, but
s.isdigit() or (s[0] in +- and
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