The dimension is arbitrary, though, so:
length = reduce(math.hypot, self._coords, 0)
Thanks, I was going to ask Algis that same question.
But still, is this solution really faster or better than the one using
list comprehension and the expression 'x*x'?
It seems to me that the above
On Fri, Jun 3, 2011 at 3:53 PM, Gabriel snoopy.6...@googlemail.com wrote:
But still, is this solution really faster or better than the one using
list comprehension and the expression 'x*x'?
No, not really.
c:\python32\python -m timeit -s coords = list(range(100)) -s from math
import hypot -s
On 6/3/11 4:53 PM, Gabriel wrote:
The dimension is arbitrary, though, so:
length = reduce(math.hypot, self._coords, 0)
Thanks, I was going to ask Algis that same question.
But still, is this solution really faster or better than the one using
list comprehension and the expression 'x*x'?
On Monday 30 May 2011 23:38:53 Gabriel wrote:
Thanks a lot to both of you, Chris Peter!
(I knew the solution would be simple ... ;-) )
import math
length = math.hypot(z, math.hypot(x, y))
One line and fast.
OldAl.
--
Algis
http://akabaila.pcug.org.au/StructuralAnalysis.pdf
--
On Thu, Jun 2, 2011 at 3:26 PM, Algis Kabaila akaba...@pcug.org.au wrote:
import math
length = math.hypot(z, math.hypot(x, y))
One line and fast.
The dimension is arbitrary, though, so:
length = reduce(math.hypot, self._coords, 0)
Cheers,
Ian
--
Well, the subject says it almost all: I'd like to write a small Vector
class for arbitrary-dimensional vectors.
I am wondering what would be the most efficient and/or most elegant
way to compute the length of such a Vector?
Right now, I've got
def length(self):
On Mon, May 30, 2011 at 2:11 AM, Gabriel snoopy.6...@googlemail.com wrote:
Well, the subject says it almost all: I'd like to write a small Vector
class for arbitrary-dimensional vectors.
I am wondering what would be the most efficient and/or most elegant
way to compute the length of such a
Gabriel wrote:
Well, the subject says it almost all: I'd like to write a small Vector
class for arbitrary-dimensional vectors.
I am wondering what would be the most efficient and/or most elegant
way to compute the length of such a Vector?
Right now, I've got
def length(self):
Thanks a lot to both of you, Chris Peter!
(I knew the solution would be simple ... ;-) )
--
http://mail.python.org/mailman/listinfo/python-list
En Mon, 30 May 2011 06:46:01 -0300, Peter Otten __pete...@web.de
escribió:
Gabriel wrote:
Well, the subject says it almost all: I'd like to write a small Vector
class for arbitrary-dimensional vectors.
class Vector(object):
... def __init__(self, *coords):
...
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