Tim Roberts wrote:
> Martin De Kauwe wrote:
>>
>>If I wanted to print an entire module, skipping the attributes
>>starting with "__" is there an *optimal* way?
>
> Your question is somewhat ambiguous. When I read "print an entire
> module", I assumed you were asking for a way to print the sourc
Trying to follow the suggestion this would be the alternate
implementation.
import sys
sys.path.append("/Users/mdekauwe/Desktop/")
import params
#params.py contains
#apples = 12.0
#cats = 14.0
#dogs = 1.3
fname = "test.asc"
try:
ofile = open(fname, 'w')
except IOError:
raise IOError("Can
Hi,
Tim yes I had a feeling my posting might be read as ambiguous! Sorry I
was trying to quickly think of a good example. Essentially I have a
set of .ini parameter files which I read into my program using
configobj, I then replace the default module parameters if the user
file is different (in my
Martin De Kauwe wrote:
>
>If I wanted to print an entire module, skipping the attributes
>starting with "__" is there an *optimal* way?
Your question is somewhat ambiguous. When I read "print an entire module",
I assumed you were asking for a way to print the source code, perhaps with
syntax co
On Sep 5, 10:06 am, Martin De Kauwe wrote:
> Hi,
>
> If I wanted to print an entire module, skipping the attributes
> starting with "__" is there an *optimal* way? Currently I am doing
> something like this. Note I am just using sys here to make the point
>
> import sys
>
> data = []
> for attr in
Hi,
If I wanted to print an entire module, skipping the attributes
starting with "__" is there an *optimal* way? Currently I am doing
something like this. Note I am just using sys here to make the point
import sys
data = []
for attr in sys.__dict__.keys():
if not attr.startswith('__') and no
