I'm using list(l) to copy the list, Tero uses l[:], but the idea is
the same.
Thanks a lot for your response and the hint.
But do you just want all proper partitions of lst? Then this is much
simpler:
lst = [0, 1, 2]
s = [(lst[:i], lst[i:]) for i in range(1, len(lst))]
Ah, thanks a lot
If you're familiar with C or C++, think of s as holding a pointer to x
which in turn holds a pointer to l and r, so when you change l or r, x
(and s indirectly) is still pointing to the same lists which by the
AH - thanks a million -- that makes it crystal clear!
[Python's apparent simplicity
Thanks a lot for your response, too.
Best regards,
Gabriel.
--
__
Life is so constructed that the event does not, cannot,
will not match the expectation. (Charlotte Bronte)
x = (list(l), list(r))
BTW: I prefer this syntax, because it makes the copy explicit, while
l[:] seems to me more implicit ...
Best regards,
Gabriel.
--
__
Life is so constructed that the event does not, cannot,
will not match
Well,
could some kind soul please explain to me why the following trivial code
is misbehaving?
#!/usr/bin/python
s = []
l = [ 0 ]
r = [0, 0]
while r:
x = (l,r)
print x
s.append( x )
l.append( r.pop(0) )
print s
The output I get is:
([0], [0, 0])
([0, 0],
Gabriel Zachmann wrote:
Well,
could some kind soul please explain to me why the following trivial code
is misbehaving?
#!/usr/bin/python
s = []
l = [ 0 ]
r = [0, 0]
while r:
x = (l,r)
print x
s.append( x )
l.append( r.pop(0) )
print s
The output I get is:
Well,
could some kind soul please explain to me why the following trivial code is
misbehaving?
#!/usr/bin/python
lst = [ 0, 1, 2 ]
s = []
l = [ lst[0] ]
r = lst[1:]
while r:
x = (l,r)
print x
s.append( x )
l.append( r.pop(0) )
print s
The output I get is:
([0], [1, 2])
On Sep 28, 11:25 pm, Gabriel Zachmann [EMAIL PROTECTED]
clausthal.de wrote:
could some kind soul please explain to me why the following trivial code is
misbehaving?
lst = [ 0, 1, 2 ]
s = []
l = [ lst[0] ]
r = lst[1:]
while r:
x = (l,r)
print x
s.append( x )
l.append(
On 9/28/07, Gabriel Zachmann [EMAIL PROTECTED] wrote:
Well,
could some kind soul please explain to me why the following trivial code is
misbehaving?
#!/usr/bin/python
lst = [ 0, 1, 2 ]
s = []
l = [ lst[0] ]
r = lst[1:]
while r:
x = (l,r)
print x
s.append( x )
