On Thu, 08 Jan 2015 09:56:50 -0800, Rustom Mody wrote:
> Given a matrix I want to shift the 1st column 0 (ie leave as is) 2nd by
> one place, 3rd by 2 places etc.
>
> This code works.
> But I wonder if numpy can do it shorter and simpler.
def shiftcols(mat):
iy,ix = np.indices(mat.shape)
On Friday, January 9, 2015 at 7:07:26 AM UTC+5:30, Ian wrote:
> On Thu, Jan 8, 2015 at 6:13 PM, Rustom Mody wrote:
> > With that I came up with the expression
> >
> > transpose(array([list(roll(mat[:,i],i,0)) for i in range(mat.shape[1])]))
> >
> > Not exactly pretty.
> > My hunch is it can be impr
On Thu, Jan 8, 2015 at 6:13 PM, Rustom Mody wrote:
> With that I came up with the expression
>
> transpose(array([list(roll(mat[:,i],i,0)) for i in range(mat.shape[1])]))
>
> Not exactly pretty.
> My hunch is it can be improved??...
Hmm, you could use the column_stack constructor to avoid having
On Friday, January 9, 2015 at 6:43:45 AM UTC+5:30, Rustom Mody wrote:
> On Friday, January 9, 2015 at 12:58:52 AM UTC+5:30, Ian wrote:
> > On Thu, Jan 8, 2015 at 10:56 AM, Rustom Mody wrote:
> > > Given a matrix I want to shift the 1st column 0 (ie leave as is)
> > > 2nd by one place, 3rd by 2 plac
On Friday, January 9, 2015 at 12:58:52 AM UTC+5:30, Ian wrote:
> On Thu, Jan 8, 2015 at 10:56 AM, Rustom Mody wrote:
> > Given a matrix I want to shift the 1st column 0 (ie leave as is)
> > 2nd by one place, 3rd by 2 places etc.
> >
> > This code works.
> > But I wonder if numpy can do it shorter a
On Thu, Jan 8, 2015 at 10:56 AM, Rustom Mody wrote:
> Given a matrix I want to shift the 1st column 0 (ie leave as is)
> 2nd by one place, 3rd by 2 places etc.
>
> This code works.
> But I wonder if numpy can do it shorter and simpler.
>
> -
> def transpose(mat):
> return(
Given a matrix I want to shift the 1st column 0 (ie leave as is)
2nd by one place, 3rd by 2 places etc.
This code works.
But I wonder if numpy can do it shorter and simpler.
-
def transpose(mat):
return([[l[i] for l in mat]for i in range(0,len(mat[0]))])
def rotate(mat):
