Peter Otten:
> which is almost identical to the last example in
> http://docs.python.org/lib/itertools-example.html
I see, thank you. I haven't had enoug time and brain to fix it (and the
OP question seemed like homework, so leaving some other things to do is
positive).
I think still that too muc
[EMAIL PROTECTED] wrote:
> If you want something less easy to understand, you can try fixing the
> following code that doesn't work:
>
> from itertools import groupby
> l = [1,2,3,5,6,8,12]
> keyf = lambda (pos,x): x-l[pos]>1
> [[el[1] for el in gr] for he,gr in groupby(enumerate(l[:-1]), keyf)]
David Hirschfield wrote:
> I have this function:
>
> def sequentialChunks(l, stride=1):
> chunks = []
> chunk = []
> for i,v in enumerate(l[:-1]):
> v2 = l[i+1]
> if v2-v == stride:
> if not chunk:
> chunk.append(v)
> chunk.append
[EMAIL PROTECTED] wrote:
> Gerard> David Hirschfield wrote:
> >> I have this function:
> >>
> >> def sequentialChunks(l, stride=1):
> ...
> >>
> >> Which takes a list of numerical values "l" and splits it into chunks
> >> where each chunk is sequential...
>
> Gerard
David Hirschfield <[EMAIL PROTECTED]> writes:
> So sequentialChunks([1,2,3,5,6,8,12]) returns:
> [[1,2,3],[5,6],[8],[12]]
Ugly and not too efficient: find the break points and use them to make
sub-lists.
def sequentialChunks(l, stride=1):
p = [0] + [i for i in xrange(1,len(l)) if l[i]-l[i-1]
Gerard> David Hirschfield wrote:
>> I have this function:
>>
>> def sequentialChunks(l, stride=1):
...
>>
>> Which takes a list of numerical values "l" and splits it into chunks
>> where each chunk is sequential...
Gerard> see the groupby example here:
G
David Hirschfield wrote:
> I have this function:
>
> def sequentialChunks(l, stride=1):
> chunks = []
> chunk = []
> for i,v in enumerate(l[:-1]):
> v2 = l[i+1]
> if v2-v == stride:
> if not chunk:
> chunk.append(v)
> chunk.append
It looks like homework. Sometimes the simpler code is better:
def splitter(seq):
if not seq:
return []
result = []
current = [seq[0]]
for pos, el in enumerate(seq[1:]):
if el - current[-1] > 1:
result.append(current[:])
current = []
c
I have this function:
def sequentialChunks(l, stride=1):
chunks = []
chunk = []
for i,v in enumerate(l[:-1]):
v2 = l[i+1]
if v2-v == stride:
if not chunk:
chunk.append(v)
chunk.append(v2)
else:
if not chunk:
