Hi,
With the following function definition, is it possible to
create an instance of class C outside the function f (and if
it is, how)? And yes, I think this is one of those times
when the real question is why :)
def f():
class C(object):
def __init__(self):
Tomi Lindberg wrote:
Hi,
With the following function definition, is it possible to
create an instance of class C outside the function f (and if
it is, how)? And yes, I think this is one of those times
when the real question is why :)
def f():
class C(object):
def __init__(self):
Tomi Lindberg wrote:
Hi,
With the following function definition, is it possible to
create an instance of class C outside the function f (and if
it is, how)?
def f():
class C(object):
def __init__(self):
self.a = 'a'
f.C = C
return C()
f.C
class
Diez B. Roggisch wrote:
No, its not. Only inside of it. And the question really is: why?
Thanks. And no need to worry, the question was intended as
fully theoretical.
--
Tomi Lindberg
--
http://mail.python.org/mailman/listinfo/python-list
Tomi Lindberg wrote:
With the following function definition, is it possible to
create an instance of class C outside the function f (and if
it is, how)? And yes, I think this is one of those times
when the real question is why :)
def f():
class C(object):
def
Peter Otten wrote:
By the way you get an instance of a different class C every time you call f,
so that
isinstance(f(), type(f())
is False.
That I didn't know. Well, that theory won't be seeing much
practice I guess.
--
Tomi Lindberg
--
Kay Schluehr wrote:
Tomi Lindberg wrote:
Hi,
With the following function definition, is it possible to
create an instance of class C outside the function f (and if
it is, how)?
def f():
class C(object):
def __init__(self):
self.a = 'a'
f.C = C
Duncan Booth [EMAIL PROTECTED] wrote in
news:[EMAIL PROTECTED]:
def f():
class C(object):
def __init__(self):
self.a = 'a'
return C()
x = f()
x.a
'a'
y=f.C()
Of course there's this:
def f():
... class C(object):
... def
