In article baa0d11c-c999-4eee-9cf5-90ad667f5...@b25g2000prb.googlegroups.com,
EK eka...@gmail.com wrote:
On Aug 20, 2:10=A0pm, Peter Otten __pete...@web.de wrote:
from itertools import izip
it =3D iter([1,2,3,4,5,6])
dict(izip(it, it))
{1: 2, 3: 4, 5: 6}
dict(zip(*[iter(l)]*2))
No,
Jan Kaliszewski wrote:
20-08-2009 o 02:05:57 Jan Kaliszewski z...@chopin.edu.pl wrote:
Or probably better:
from itertools import islice, izip
dict(izip(islice(li, 0, None, 2), islice(li, 1, None, 2)))
Or similarly, perhaps more readable:
iterator = iter(li)
On Thu, 20 Aug 2009 08:10:28 +0200, Peter Otten wrote:
I just can't stop posting this one:
from itertools import izip
it = iter([1,2,3,4,5,6])
dict(izip(it, it))
{1: 2, 3: 4, 5: 6}
I really tried, but yours drove me over the edge.
If you want something to drive you over the edge:
Peter Otten wrote:
it = iter([1,2,3,4,5,6])
dict(izip(it, it))
{1: 2, 3: 4, 5: 6}
devoZip(it). Zip(it) good./devo
it's-3:00am-and-i-seriously-need-to-sleep'ly yers...
-tkc
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Steven D'Aprano wrote:
On Thu, 20 Aug 2009 08:10:28 +0200, Peter Otten wrote:
I just can't stop posting this one:
from itertools import izip
it = iter([1,2,3,4,5,6])
dict(izip(it, it))
{1: 2, 3: 4, 5: 6}
I really tried, but yours drove me over the edge.
If you want something to
On Aug 20, 9:10 am, Peter Otten __pete...@web.de wrote:
Jan Kaliszewski wrote:
20-08-2009 o 02:05:57 Jan Kaliszewski z...@chopin.edu.pl wrote:
Or probably better:
from itertools import islice, izip
dict(izip(islice(li, 0, None, 2), islice(li, 1, None, 2)))
Or similarly,
Hi all,
I need to create a dictionary out of a list.
Given the list [1, 2, 3, 4, 5, 6]
I need the dictionary: {1:2, 3:4, 5:6}
I'll appreciate your help
Thanks
iu2
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iu2 schrieb:
Hi all,
I need to create a dictionary out of a list.
Given the list [1, 2, 3, 4, 5, 6]
I need the dictionary: {1:2, 3:4, 5:6}
dict(zip(l[::2], l[1::2]))
Diez
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On Aug 19, 11:39 pm, Diez B. Roggisch de...@nospam.web.de wrote:
iu2 schrieb:
Hi all,
I need to create a dictionary out of a list.
Given the list [1, 2, 3, 4, 5, 6]
I need the dictionary: {1:2, 3:4, 5:6}
dict(zip(l[::2], l[1::2]))
Diez
Wow, this is cool!
thanks
iu2
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19-08-2009 o 22:52:54 iu2 isra...@elbit.co.il wrote:
On Aug 19, 11:39 pm, Diez B. Roggisch de...@nospam.web.de wrote:
iu2 schrieb:
Hi all,
I need to create a dictionary out of a list.
Given the list [1, 2, 3, 4, 5, 6]
I need the dictionary: {1:2, 3:4, 5:6}
dict(zip(l[::2], l[1::2]))
20-08-2009 o 02:05:57 Jan Kaliszewski z...@chopin.edu.pl wrote:
Or probably better:
from itertools import islice, izip
dict(izip(islice(li, 0, None, 2), islice(li, 1, None, 2)))
Or similarly, perhaps more readable:
iterator = iter(li)
dict((iterator.next(),
In [EMAIL PROTECTED], half.italian
wrote:
[entries.__setitem__(int(d.date.strftime('%m'))], d.id) for d in
links]
btw...I was curious of this too. I used 'dir(dict)' and looked for a
method that might do what we wanted and bingo!
This is really ugly. Except `__init__()` it's always a
Example:
a = [1,2,3,4,5,6,7,8,9,10]
aDict = dict([(x,x+1) for x in a if x%2==0])
print aDict
When I run this program I get:
{8: 9, 2: 3, 4: 5, 10: 11, 6: 7}
why this output isn't ordered, giving:
{2: 3, 4: 5, 6: 7, 8: 9, 10: 11 }
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Pierre Quentel a écrit :
On 27 mai, 22:55, erikcw [EMAIL PROTECTED] wrote:
Hi,
I'm trying to turn o list of objects into a dictionary using a list
comprehension.
...
entries = dict([ (int(d.date.strftime('%m')),d.id) for d in links] )
With Python2.4 and above you can use a generator
En Mon, 28 May 2007 05:20:16 -0300, Wim Vogelaar
[EMAIL PROTECTED] escribió:
Example:
a = [1,2,3,4,5,6,7,8,9,10]
aDict = dict([(x,x+1) for x in a if x%2==0])
print aDict
When I run this program I get:
{8: 9, 2: 3, 4: 5, 10: 11, 6: 7}
why this output isn't ordered, giving:
{2: 3,
why this output isn't ordered, giving:
{2: 3, 4: 5, 6: 7, 8: 9, 10: 11 }
I made the original list two elements longer: a =
[1,2,3,4,5,6,7,8,9,10,11,12]
and to my surprise the output is now ordered, giving: {2: 3, 4: 5, 6: 7, 8:
9, 10: 11, 12: 13}
I am running ActiveState ActivePython
On May 28, 12:25 am, Marc 'BlackJack' Rintsch [EMAIL PROTECTED] wrote:
In [EMAIL PROTECTED], half.italian
wrote:
[entries.__setitem__(int(d.date.strftime('%m'))], d.id) for d in
links]
btw...I was curious of this too. I used 'dir(dict)' and looked for a
method that might do what we
[EMAIL PROTECTED] wrote:
Do you think we just shouldn't use list comprehensions to build
dictinaries at all? Or is Stefan's solution acceptable (and pythonic)?
Use list comprehensions where you need the resulting list; if you want
nothing but the side effects, use a for loop.
[Stefan
En Mon, 28 May 2007 05:37:12 -0300, Wim Vogelaar
[EMAIL PROTECTED] escribió:
I made the original list two elements longer: a =
[1,2,3,4,5,6,7,8,9,10,11,12]
and to my surprise the output is now ordered, giving: {2: 3, 4: 5, 6: 7,
8:
9, 10: 11, 12: 13}
I am running ActiveState
Wim Vogelaar wim.vogelaar at mc2world dot org wrote:
why this output isn't ordered, giving:
{2: 3, 4: 5, 6: 7, 8: 9, 10: 11 }
I made the original list two elements longer: a =
[1,2,3,4,5,6,7,8,9,10,11,12]
and to my surprise the output is now ordered, giving: {2: 3, 4: 5, 6:
7, 8:
Hi,
I'm trying to turn o list of objects into a dictionary using a list
comprehension.
Something like
entries = {}
[entries[int(d.date.strftime('%m'))] = d.id] for d in links]
I keep getting errors when I try to do it. Is it possible? Do
dictionary objects have a method equivalent to
On May 27, 1:55 pm, erikcw [EMAIL PROTECTED] wrote:
Hi,
I'm trying to turn o list of objects into a dictionary using a list
comprehension.
Something like
entries = {}
[entries[int(d.date.strftime('%m'))] = d.id] for d in links]
I keep getting errors when I try to do it. Is it
erikcw schrieb:
Hi,
I'm trying to turn o list of objects into a dictionary using a list
comprehension.
Something like
entries = {}
[entries[int(d.date.strftime('%m'))] = d.id] for d in links]
I keep getting errors when I try to do it. Is it possible? Do
dictionary objects have a
On 27 mai, 22:55, erikcw [EMAIL PROTECTED] wrote:
Hi,
I'm trying to turn o list of objects into a dictionary using a list
comprehension.
Something like
entries = {}
[entries[int(d.date.strftime('%m'))] = d.id] for d in links]
I keep getting errors when I try to do it. Is it possible?
[Roy Smith]
I also think the published description is needlessly confusing. Why does
it use
{'one': 2, 'two': 3}
as the example mapping when
{'one': 1, 'two': 2}
would illustrate exactly the same point but be easier to comprehend. The
mapping given is the kind of thing I would
[Roy Smith]
I also think the published description is needlessly confusing. Why does
it use
{'one': 2, 'two': 3}
as the example mapping when
{'one': 1, 'two': 2}
would illustrate exactly the same point but be easier to comprehend. The
mapping given is the kind of thing I would
On Friday 24 June 2005 05:26 pm, infidel wrote:
dict((x, None) for x in alist)
or if you want it to run in 2.3 (before generator
expressions):
dict( [(x,None) for x in alist] )
Before the dict constructor, you needed to do this:
d={}
for key in alist:
d[key]=None
which is still only 3
Terry Hancock [EMAIL PROTECTED] wrote:
Before the dict constructor, you needed to do this:
d={}
for key in alist:
d[key]=None
I just re-read the documentation on the dict() constructor. Why does it
support keyword arguments?
dict(foo=bar, baz=blah) == {foo:bar, baz=blah}
This
Roy Smith [EMAIL PROTECTED] wrote:
I just re-read the documentation on the dict() constructor. Why does it
support keyword arguments?
dict(foo=bar, baz=blah) == {foo:bar, baz=blah}
This smacks of creeping featurism. Is this actually useful in real code?
It took me several readings of
On Sat, 25 Jun 2005 09:10:33 -0400, Roy Smith [EMAIL PROTECTED] wrote:
Terry Hancock [EMAIL PROTECTED] wrote:
Before the dict constructor, you needed to do this:
d={}
for key in alist:
d[key]=None
I just re-read the documentation on the dict() constructor. Why does it
support keyword
Roy Smith wrote:
I just re-read the documentation on the dict() constructor. Why does it
support keyword arguments?
dict(foo=bar, baz=blah) == {foo:bar, baz=blah}
This smacks of creeping featurism. Is this actually useful in real code?
Personally, I use it all the time. It's a
Roy Smith wrote:
Terry Hancock [EMAIL PROTECTED] wrote:
...
I just re-read the documentation on the dict() constructor. Why does it
support keyword arguments?
dict(foo=bar, baz=blah) == {foo:bar, baz=blah}
This smacks of creeping featurism. Is this actually useful in real code?
Yes
On Sat, 25 Jun 2005 06:44:22 -0700, George Sakkis wrote:
Roy Smith [EMAIL PROTECTED] wrote:
I just re-read the documentation on the dict() constructor. Why does it
support keyword arguments?
dict(foo=bar, baz=blah) == {foo:bar, baz=blah}
This smacks of creeping featurism. Is this
Steven D'Aprano wrote:
On Sat, 25 Jun 2005 06:44:22 -0700, George Sakkis wrote:
Roy Smith [EMAIL PROTECTED] wrote:
I just re-read the documentation on the dict() constructor. Why does it
support keyword arguments?
dict(foo=bar, baz=blah) == {foo:bar, baz=blah}
This smacks of
I know there must be a better way to phrase this so google understands, but
I don't know how.. So I'll ask people.
Assume I have a list object called 'alist'.
Is there an easy way to create a dictionary object with the members of
'alist' being the keys in the dictionary, and the value of the
David Bear wrote:
Assume I have a list object called 'alist'.
Is there an easy way to create a dictionary object with the members of
'alist' being the keys in the dictionary, and the value of the keys set to
null?
You mean None, right? :)
a_list = [1, 2, 3, 'a', 'b', 'c']
dict((x, None) for x in alist)
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David Bear wrote:
Is there an easy way to create a dictionary object with the members of
'alist' being the keys in the dictionary, and the value of the keys set to
null?
adict = dict.fromkeys(alist)
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David Bear wrote:
I know there must be a better way to phrase this so google understands, but
I don't know how.. So I'll ask people.
Assume I have a list object called 'alist'.
Is there an easy way to create a dictionary object with the members of
'alist' being the keys in the dictionary,
Rocco Moretti wrote:
Are you sure you need a dictionary? You may want to look at the Set
module instead, if the values aren't important.
Set is the name of the type in the module sets, introduced in 2.3.
Since 2.4 you can use the builtin set type. Here's the import snippet
that works for 2.3
On 2005-06-24, infidel [EMAIL PROTECTED] wrote:
dict((x, None) for x in alist)
Whoa, I thought dictionary comprehensions were still planned feature. I
guess I gotta start paying closer attention.
Dave Cook
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Dave Cook wrote:
On 2005-06-24, infidel [EMAIL PROTECTED] wrote:
dict((x, None) for x in alist)
Whoa, I thought dictionary comprehensions were still planned feature. I
guess I gotta start paying closer attention.
Added in Python 2.4, it's actually a generator expression as the sole
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