Hello,
I ran the following code (Using Debian 5.0)
from numpy import *
a = arange(1.,10.)
b = reshape(a, [3,3])
c = linalg.inv(b)
print b
print c
print dot(b,c)
print dot(c,b)
And the result is
[[ 1. 2. 3.]
[ 4. 5. 6.]
[ 7. 8. 9.]]
[[ 3.15221191e+15 -6.30442381e+15 3.15221191e+15]
[
On Jun 6, 3:34 pm, Ajith Kumar aj...@iuac.res.in wrote:
Hello,
I ran the following code (Using Debian 5.0)
from numpy import *
a = arange(1.,10.)
b = reshape(a, [3,3])
c = linalg.inv(b)
print b
print c
print dot(b,c)
print dot(c,b)
And the result is
[[ 1. 2. 3.]
[ 4. 5. 6.]
Ajith Kumar aj...@iuac.res.in wrote:
I ran the following code (Using Debian 5.0)
from numpy import *
a = arange(1.,10.)
b = reshape(a, [3,3])
c = linalg.inv(b)
print b
print c
print dot(b,c)
print dot(c,b)
And the result is
[[ 1. 2. 3.]
[ 4. 5. 6.]
[ 7. 8.
On 2009-06-06 00:34, Ajith Kumar wrote:
Hello,
I ran the following code (Using Debian 5.0)
from numpy import *
Please ask numpy questions on the numpy mailing list, not here:
http://www.scipy.org/Mailing_Lists
a = arange(1.,10.)
b = reshape(a, [3,3])
c = linalg.inv(b)
print b
print c
Ajith Kumar wrote:
[[ 1. 2. 3.]
[ 4. 5. 6.]
[ 7. 8. 9.]]
Another way to see that this is singular is notice or calculate that
(1,2,3) - 2*(4,5,6) + (7,8,9) = (0,0,0)
Same is true for the columns.
--
http://mail.python.org/mailman/listinfo/python-list
Robert Kern robert.kern at gmail.com writes:
On 2009-06-06 00:34, Ajith Kumar wrote:
from numpy import *
Please ask numpy questions on the numpy mailing list, not here:
http://www.scipy.org/Mailing_Lists
a = arange(1.,10.)
b = reshape(a, [3,3])
c = linalg.inv(b)
And the
On Jun 6, 3:31 pm, Robert Kern robert.k...@gmail.com wrote:
On 2009-06-06 17:09, John Machin wrote:
Robert Kernrobert.kernat gmail.com writes:
You have a very singular matrix (2*a[1] - a[0] == a[2]). You cannot invert
it
numerically and expect sensible results.
Is raising an
