Would anyone else find this syntax useful for generator expressions?
py [x for x in '1234' if x%2 else 'even']
[1, 'even', 3, 'even']
I'm guessing this has been suggested before?
James
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James Stroud [EMAIL PROTECTED] writes:
py [x for x in '1234' if x%2 else 'even']
[1, 'even', 3, 'even']
I'm guessing this has been suggested before?
You could (in 2.5) use:
[(x if x%2 else 'even') for x in '1234']
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James Stroud wrote:
Would anyone else find this syntax useful for generator expressions?
py [x for x in '1234' if x%2 else 'even']
[1, 'even', 3, 'even']
I'm guessing this has been suggested before?
James
Before anyone notices, I should say:
[x for x in [1,2,3,4] if x%2 else 'even']
py [x for x in '1234' if x%2 else 'even']
[1, 'even', 3, 'even']
I'm guessing this has been suggested before?
You could (in 2.5) use:
[(x if x%2 else 'even') for x in '1234']
This failed on multiple levels in 2.3.5 (the if syntax is
unrecognized, and trying the below with '1234'
As Paul already demonstrated, this is hardly needed since it can be
done more clearly with existing lang. features.
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You could (in 2.5) use:
[(x if x%2 else 'even') for x in '1234']
Or this:
[int(x)1 and x or 'even' for x in '1234']
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Tim Chase [EMAIL PROTECTED] writes:
You could (in 2.5) use:
[(x if x%2 else 'even') for x in '1234']
This failed on multiple levels in 2.3.5 (the if syntax is
unrecognized,
Yes, that syntax is new to 2.5.
However, this worked in my 2.3.5:
[((x%2 == 0 and 'even') or x) for x in
