Terry Reedy wrote:
> Bryan wrote:
>
>> How come dir(Foo) does not show __name__? That is how I was
>> investigating the possibilities.
>
> Interesting question. Seems like an oversight. dir(some_module) and
> dir(some_function) include '__name__'. I suggest you search the tracker
> for existing
Bryan wrote:
How come dir(Foo) does not show __name__? That is how I was
investigating the possibilities.
Interesting question. Seems like an oversight. dir(some_module) and
dir(some_function) include '__name__'. I suggest you search the tracker
for existing issues on this subject and add a
Try Foo.__name__ if Foo is a class object.
On 6/24/09, Bryan wrote:
> Given a class:
>
> class Foo(object):
> pass
>
> How can I get the name "Foo" without having an instance of the class?
>
> str(Foo) gives me more than just the name Foo. "__main__.Account"
> Foo.__class__.__name__ gives m
On Wed, 2009-06-24 at 09:17 -0700, Bryan wrote:
> Given a class:
>
> class Foo(object):
> pass
>
> How can I get the name "Foo" without having an instance of the class?
>
> str(Foo) gives me more than just the name Foo. "__main__.Account"
> Foo.__class__.__name__ gives me "type"
>
> I don
On Jun 24, 9:25 am, Tim Golden wrote:
> Bryan wrote:
> > Given a class:
>
> > class Foo(object):
> > pass
>
> > How can I get the name "Foo" without having an instance of the class?
>
> > str(Foo) gives me more than just the name Foo. "__main__.Account"
> > Foo.__class__.__name__ gives me "t
Bryan wrote:
Given a class:
class Foo(object):
pass
How can I get the name "Foo" without having an instance of the class?
str(Foo) gives me more than just the name Foo. "__main__.Account"
Foo.__class__.__name__ gives me "type"
I don't want to do:
Foo().__class__.__name__ if possible. I
Bryan wrote:
Given a class:
class Foo(object):
pass
How can I get the name "Foo" without having an instance of the class?
str(Foo) gives me more than just the name Foo. "__main__.Account"
Foo.__class__.__name__ gives me "type"
I don't want to do:
Foo().__class__.__name__ if possible. I
Given a class:
class Foo(object):
pass
How can I get the name "Foo" without having an instance of the class?
str(Foo) gives me more than just the name Foo. "__main__.Account"
Foo.__class__.__name__ gives me "type"
I don't want to do:
Foo().__class__.__name__ if possible. I would rather a
