I'm doing:
a = now()
delta = ReltaiveDateTime(days=+6, weekday(mx.DateTime.Friday, 0))
Next Friday: a+delta
a: march 23
a+delta: Gives me March 31st and not March 24th
Any ideas?
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I figured out how to do it. This does not work:
delta = ReltaiveDateTime(days=0, weekday(mx.DateTime.Friday, 0))
But this works:
delta = ReltaiveDateTime(days=+0, weekday(mx.DateTime.Friday, 0))
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On 24/03/2006 5:18 AM, Dennis Lee Bieber wrote:
On 23 Mar 2006 09:37:13 -0800, vj [EMAIL PROTECTED] declaimed the
following in comp.lang.python:
I'm doing:
a = now()
delta = ReltaiveDateTime(days=+6, weekday(mx.DateTime.Friday, 0))
Next Friday: a+delta
a: march 23
a+delta: Gives me March
Thanks for pointing out that the days=+0 is not necessary. Your other
points are well noted.
Thanks
VJ
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On 24/03/2006 6:30 AM, vj wrote:
I figured out how to do it. This does not work:
delta = ReltaiveDateTime(days=0, weekday(mx.DateTime.Friday, 0))
But this works:
delta = ReltaiveDateTime(days=+0, weekday(mx.DateTime.Friday, 0))
vj, NEITHER of those work, because you still have the two
a = now()
delta = ReltaiveDateTime(days=+6, weekday(mx.DateTime.Friday, 0))
Next Friday: a+delta
a: march 23
a+delta: Gives me March 31st and not March 24th
Any ideas?
Just an off-beat idea: use Python's datetime instead of mx.DateTime,
and my recur module:
