On Apr 3, 12:26 pm, Alain Ketterlin
wrote:
> nn writes:
> >> > for item in tag23gr:
> >> > ... value, key = tuple(item)
> >> > ... if(g23tag.get(key)):
> >> > ... g23tag[key].append(value)
> >> > ... else:
> >> > ... g23tag[key] = [value]
>
> >>
nn writes:
>> > for item in tag23gr:
>> > ... value, key = tuple(item)
>> > ... if(g23tag.get(key)):
>> > ... g23tag[key].append(value)
>> > ... else:
>> > ... g23tag[key] = [value]
>>
>> for item in tag23gr:
>> g23tag.setdefault(item[0],[]).
On Apr 3, 11:02 am, Alain Ketterlin
wrote:
> python writes:
> > tag23gr is a list of lists each with two items.
> > g23tag is an empty dictionary when I run the for loop below.
> > When is is complete each key is a graphic name who's values are a list
> > of tags.
>
> > for item in tag23gr:
> > .
python wrote:
> I played around with a few things and this works but was wondering if
> there was a better way to do this.
> My first thought was list comprehension but could not get a figure out
> the syntax.
>
> tag23gr is a list of lists each with two items.
> g23tag is an empty dictionary whe
On Wed, Apr 4, 2012 at 12:36 AM, python wrote:
> for item in tag23gr:
> ... value, key = tuple(item)
> ... if(g23tag.get(key)):
> ... g23tag[key].append(value)
> ... else:
> ... g23tag[key] = [value]
Simple enhancement: Use setdefault. Instead of the if, just u
python writes:
> tag23gr is a list of lists each with two items.
> g23tag is an empty dictionary when I run the for loop below.
> When is is complete each key is a graphic name who's values are a list
> of tags.
>
> for item in tag23gr:
> ... value, key = tuple(item)
> ... if(g23tag.get(key))
I played around with a few things and this works but was wondering if
there was a better way to do this.
My first thought was list comprehension but could not get a figure out
the syntax.
tag23gr is a list of lists each with two items.
g23tag is an empty dictionary when I run the for loop below.
W
