Thank you very much!
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LJ wrote:
> Thank you for the reply.
>
> So, as long as I access and modify the elements of, for example,
>
> A=array([[set([])]*4]*3)
>
>
> as (for example):
>
> a[0][1] = a[0][1] | set([1,2])
>
> or:
>
> a[0][1]=set([1,2])
>
> then I should have no problems?
As long as you set (i. e. re
Thank you for the reply.
So, as long as I access and modify the elements of, for example,
A=array([[set([])]*4]*3)
as (for example):
a[0][1] = a[0][1] | set([1,2])
or:
a[0][1]=set([1,2])
then I should have no problems?
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LJ wrote:
> Wolfgang, thank you very much for your reply.
>
> Following the example in the link, the problem appears:
>
A = [[0]*2]*3
You can see this as a shortcut for
value = 0
inner = [value, value]
A = [inner, inner, inner]
When the value is mutable (like your original set) a modific
Wolfgang, thank you very much for your reply.
Following the example in the link, the problem appears:
>>> A = [[0]*2]*3
>>> A
[[0, 0], [0, 0], [0, 0]]
>>> A[0][0] = 5
>>> A
[[5, 0], [5, 0], [5, 0]]
Now, if I use a numpy array:
>>> d=array([[0]*2]*3)
>>> d
array([[0, 0],
[0, 0],
[0
On 25.05.2014 00:14, Robert Kern wrote:
On 2014-05-24 23:05, Luis José Novoa wrote:
Hi All,
Hope you're doing great. One quick question. I am defining an array of
sets using numpy as:
a=array([set([])]*3)
Has nothing to do with numpy, but the problem is exclusively with your
innermost expr
On 2014-05-24 23:05, Luis José Novoa wrote:
Hi All,
Hope you're doing great. One quick question. I am defining an array of sets
using numpy as:
a=array([set([])]*3)
Now, if I want to add an element to the set in, lets say, a[0], and I use the
.add(4) operation, which results in:
array([set(
Hi All,
Hope you're doing great. One quick question. I am defining an array of sets
using numpy as:
a=array([set([])]*3)
Now, if I want to add an element to the set in, lets say, a[0], and I use the
.add(4) operation, which results in:
array([set([4]), set([4]), set([4])], dtype=object)
whi
