Jan Danielsson:
...completely avoiding the design issue I raised altogether. Thanks!
Exactly what I was hoping for! :-)
Another common way to do it, it may be a little slower because that
n,txt is a tuple:
items = set(int(n) for n,txt in mylist)
Bye,
bearophile
--
Hello all,
I have a list which contains a bunch of tuples:
mylist = [ ('1', 'Foobar'), ('32', 'Baz'), ('4', 'Snorklings') ]
(The list can potentially be shorter, or much longer). Now I want to
take the first element in each tuple and store it in a list (to use in a
Set later on).
Jan Danielsson:
newlist = [ None ] * len(mylist)
for i in range(len(mylist)):
newlist.append(int(e[0]))
Note that this appends after the Nones, not over them. And note that
here the name 'e' is undefined.
The most used idiom for that is:
newlist = [int(e[0]) for e in mylist]
Or
[EMAIL PROTECTED] wrote:
newlist = [ None ] * len(mylist)
for i in range(len(mylist)):
newlist.append(int(e[0]))
Note that this appends after the Nones, not over them. And note that
here the name 'e' is undefined.
What an idiot I am.. Yes, I know that.. And I actually *had*
