Maciej Bliziński a écrit :
(snip the rest - already answered by at least 3 persons).
> I
> don't want to expose the __bar() function outside, but on the other
> hand i want to defer its implementation to a subclass. It seems like I
> need to make it public, doesn't it?
First, keep in mind that th
On 2007-07-16, Maciej Blizi?ski <[EMAIL PROTECTED]> wrote:
> Hello,
>
> I've come across something that I don't quite understand about
> Python's inheritance. Consider the following code snippet:
>
> class A(object):
> def call_bar(self): return self.bar()
> def call___bar(self): return sel
Maciej Bliziński wrote:
> Hello,
>
> I've come across something that I don't quite understand about
> Python's inheritance. Consider the following code snippet:
>
> class A(object):
> def call_bar(self): return self.bar()
> def call___bar(self): return self.__bar()
> def __bar(self):
Maciej Blizi?ski wrote:
> calling B::call_bar(): B::bar()
> calling B::call___bar(): A::__bar()
(BTW, there is no :: operator in Python. It should be, e. g.,
B.bar().)
> In the latter case, it calls the base class' implementation. It
> probably goes along with Python's spec, but I found it surp
Hello,
I've come across something that I don't quite understand about
Python's inheritance. Consider the following code snippet:
class A(object):
def call_bar(self): return self.bar()
def call___bar(self): return self.__bar()
def __bar(self): return "A::__bar()"
def bar(self): ret
