On Thu, Dec 7, 2017 at 5:11 AM, Peter Otten <__pete...@web.de> wrote:
> Chris Angelico wrote:
>
>> On Thu, Dec 7, 2017 at 3:56 AM, Dennis Lee Bieber
>> wrote:
>>> Granted, the statistics module in newer Python releases makes the
>>> entire assignment trivial...
>>>
>>> ClgubaJva 3.5.3 (qrs
On Wed, Dec 6, 2017, ssghotra1997 wrote:
import random
def rollDie(num):
sides = {'One':0, 'Two':0,'Three':0,'Four':0,'Five':0,'Six':0}
for i in range(num):
rolls = int(random.randint(1, 6)
if rolls == 1:
sides['One'] += 1
if rolls == 2:
si
Chris Angelico wrote:
> On Thu, Dec 7, 2017 at 3:56 AM, Dennis Lee Bieber
> wrote:
>> Granted, the statistics module in newer Python releases makes the
>> entire assignment trivial...
>>
>> ClgubaJva 3.5.3 (qrsnhyg, Wha 26 2017, 16:17:54) [ZFP i.1900 64 ovg
>> (NZQ64)] ba jva32.
>
> Is t
On Thu, Dec 7, 2017 at 3:56 AM, Dennis Lee Bieber wrote:
> Granted, the statistics module in newer Python releases makes the
> entire assignment trivial...
>
> ClgubaJva 3.5.3 (qrsnhyg, Wha 26 2017, 16:17:54) [ZFP i.1900 64 ovg
> (NZQ64)] ba jva32.
Is this from the Function Call of Cthulu
I think I also came up with 4 as "the most frequent number".
It is unclear ot me how you came up with 3.36 as the most common number,
because I tried rolling a six-sided die myself several times,
and somehow 3.36 didn't come up even once!
On Wed, Dec 6, 2017, D'Arcy Cain wrote:
>
On 12/05/2017 0
