On 16/12/2009 12:49, stefan.messerl...@postfinance.ch wrote: > I have the following error and no clue, how to solve that. Up to python > version 2.5 the following script worked without an error, but since python > 2.6. I get the following error: > > #!/usr/bin/env python > # -*- coding: ISO-8859-1 -*- > import logging > logging.getLogger().addHandler( logging.StreamHandler() ) > log = logging.getLogger() > t = "äöü" > print "this is printed : " + t > log.error( "this is log.error : " + t ) > > > > # running the above script with Python 2.5 > $ ./x.py > this is printed : äöü > this is log.error : äöü > > > # running the above script with Python 2.6 > $ ./x.py > this is printed : äöü > Traceback (most recent call last): > File > "/var/tmp/pf-python-2.6-2.6.1-root/appl_local/python-2.6/lib/python2.6/logging/__init__.py", > line 765, in emit > UnicodeDecodeError: 'ascii' codec can't decode byte 0xe4 in position 20: > ordinal not in range(128) > > > I found your answer of issue6991 in bugs.python.org, where somebody had a > similar problem, but to be honest, I have no idea how to solve my problem. > > Can you please give me a tip what I have to change or where I can find more > information ? >
Hello Stefan, You should pass a stream to StreamHandler which has an encoding attribute set to the appropriate encoding (presumably iso-8859-1) and ensure that your stream will encode any Unicode sent to it with that encoding. For example, import codecs ENCODING = 'iso-8859-1' # or whatever writer = codecs.getwriter(ENCODING) w = writer(sys.stderr) w.encoding = ENCODING ... handler = logging.StreamHandler(w) ... In future, please ask questions like this on comp.lang.python (python-list@python.org) to give others the chance to participate in any discussion. Regards, Vinay Sajip -- http://mail.python.org/mailman/listinfo/python-list
