Glen wrote:
#!/usr/local/bin/python
import sys
print "1.\tDo Something"
print "2.\tDo Something"
print "3.\tDo Something"
print "4.\tDo Something"
print "5.\tDo Something"
print "6.\tExit"
choice=raw_input("Please Enter Choice: ")
if int(choice)==1:
print "Here"
else:
pass
if int(choice)==2:
Glen wrote:
#!/usr/local/bin/python
import sys
print "1.\tDo Something"
print "2.\tDo Something"
print "3.\tDo Something"
print "4.\tDo Something"
print "5.\tDo Something"
print "6.\tExit"
choice=raw_input("Please Enter Choice: ")
if int(choice)==1:
print "Here"
else:
pass
if int(choice)==2:
>if int(choice)==2:
>else:
> pass
if int(choice)==2:
print "Here" # <== There should be some statement present after the
# if condition. Likewise place this statement in
# all other if conditions
else:
pass
HTH,
Vishnu
-Original Message--
"Glen" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED]
if int(choice)==2:
else:
pass
File "./Code.py", line 20
else:
^
IndentationError: expeted an indented block
What am I doing wrong?
As the error trace informs you, Python expexts an indented block. You need
to put something
