On 12/15/2022 11:34 PM, MRAB wrote:
On 2022-12-15 22:49, Gronicus@SGA.Ninja wrote:
Yes, it works like a charm. On the tupility of it all.
Special thanks for the explanation too…..
(Originally asked but I found the errors. All is working)
Now that the code no longer produces the errors, I see
On 2022-12-15 22:49, Gronicus@SGA.Ninja wrote:
Yes, it works like a charm. On the tupility of it all.
Special thanks for the explanation too…..
(Originally asked but I found the errors. All is working)
Now that the code no longer produces the errors, I see that the year and month
not
+ ">")
if hours > 7:
print(" Time to inject Humulin R u500.")
pause = input("Pause")
# ==
-Original Message-
From: Python-list On
Behalf Of Thomas Passin
Sent: Tuesday, December 13, 2022 1
this?
From: anthony.flury
Sent: Thursday, December 15, 2022 1:47 PM
To: Gronicus@SGA.Ninja
Subject: RE: Subtracting dates to get hours and minutes
What is likely happening is that when you read the data from the file you are
not reading a tuple, you are reading a 26 charcter string.
You have
, December 15, 2022 at 5:02 PM
To: 'anthony.flury' , python-list@python.org
Subject: RE: Subtracting dates to get hours and minutes
*** Attention: This is an external email. Use caution responding, opening
attachments or clicking on links. ***
Yes, it works like a charm. On the tupility of it all
PM
To: Gronicus@SGA.Ninja
Subject: RE: Subtracting dates to get hours and minutes
What is likely happening is that when you read the data from the file you are
not reading a tuple, you are reading a 26 charcter string.
You have to convert that string into a tuple - the easiest way
nutes = minutes - 60
hours += 1
minutes = round(minutes)
print ("77 Hours = <" + str(hours) + ">")
print ("78 Minutes = <" + str(minutes) + ">")
if hours > 7:
print(" Time to inject Humulin R u500.")
pause = input("Pause")
# =
hours = 0
while (minutes > 59):
minutes = minutes - 60
hours += 1
minutes = round(minutes)
print ("77 Hours = <" + str(hours) + ">")
print ("78 Minutes = <" + str(minutes) + ">")
if hours > 7:
print(" Ti
<" + str(hours) + ">")
print ("78 Minutes = <" + str(minutes) + ">")
if hours > 7:
print(" Time to inject Humulin R u500.")
pause = input("Pause")
# ==
---
ember 13, 2022 11:20 PM
To: python-list@python.org
Subject: Re: Subtracting dates to get hours and minutes
Your problem is that datetime.datetime does not accept a tuple as an
argument. It expects an integer value for the first argument, but you
supplied a tuple. In Python, you can use a sequence
assin
Sent: Tuesday, December 13, 2022 11:20 PM
To: python-list@python.org
Subject: Re: Subtracting dates to get hours and minutes
Your problem is that datetime.datetime does not accept a tuple as an
argument. It expects an integer value for the first argument, but you
supplied a tuple. In Python, y
Your problem is that datetime.datetime does not accept a tuple as an
argument. It expects an integer value for the first argument, but you
supplied a tuple. In Python, you can use a sequence (e.g., tuple or
list) the way you want by prefixing it with an asterisk. This causes
the sequence of
As is, Test A works.
Comment out Test A and uncomment Test B it fails.
In Test B, I move the data into a variable resulting with the report:
"TypeError: an integer is required (got type tuple)
How do I fix this?
on
behalf of Marc Lucke
Date: Monday, December 12, 2022 at 11:37 AM
To: python-list@python.org
Subject: Re: Subtracting dates to get hours and minutes
*** Attention: This is an external email. Use caution responding, opening
attachments or clicking on links. ***
my approach would be to convert your
my approach would be to convert your two date/times to seconds from
epoch - e.g.
https://www.geeksforgeeks.org/convert-python-datetime-to-epoch/ - then
subtract the number, divide the resultant by 3600 (hours) & get the
modulus for minutes. There's probably a standard function - it should
be
I have seen vast conversations on this topic but if everything is in the same
time-zone and daylight saving switchovers are not involved it is relatively
straightforward.Check the timedelta docs. Or convert datetimes to ordinals and
subtract then convert the result to whatever units please
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