Say : line = abcdabcd#12 adssda
index = line.find('#')
num = line[index:index+2]
num will now be 12.
Likewise I want to read the number after the '#' and store it in num. The
problem is that the number can be a 1/2/3/4 digit number. So is there a way in
which I can define num so
On 10/12/2010 10:48 PM, Pratik Khemka wrote:
Likewise I want to read the number after the '#' and store it in num. The
problem is that the number can be a 1/2/3/4 digit number. So is there a way in
which I can define num so that it contains the number after '#' irrespective of
how many digits
On Tue, Oct 12, 2010 at 1:48 PM, Pratik Khemka pratikkhe...@hotmail.com wrote:
Say : line = abcdabcd#12 adssda
index = line.find('#')
num = line[index:index+2]
num will now be 12.
No, num will be #1. You wanted:
num = line[index+1:index+3]
Likewise I want to read the number after the '#'
