I extracted an isolated problem from a slightly more complex
situation, that's why I'm using REs.
Thank you all for your help, my problem is now solved.
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Hi all,
suppose I have:
s='a=b, c=d'
and I want to extract sub-strings a,b,c and d from s (and in general
from any longer list of such comma separated pairs).
Some failed attempts:
In [12]: re.findall(r'(.+)=(.+)', s)
Out[12]: [('a=b, c', 'd')]
In [13]: re.findall(r'(.+?)=(.+)', s)
Out[13]:
On Wednesday, December 22, 2010 12:22:22 PM UTC-4, Francesco Napolitano wrote:
Hi all,
suppose I have:
s='a=b, c=d'
and I want to extract sub-strings a,b,c and d from s (and in general
from any longer list of such comma separated pairs).
Some failed attempts:
In [12]:
2010/12/22 Ciccio franap...@gmail.com:
Hi all,
suppose I have:
s='a=b, c=d'
and I want to extract sub-strings a,b,c and d from s (and in general from
any longer list of such comma separated pairs).
Some failed attempts:
In [12]: re.findall(r'(.+)=(.+)', s)
Out[12]: [('a=b, c', 'd')]
Ciccio franap...@gmail.com writes:
suppose I have:
s='a=b, c=d'
and I want to extract sub-strings a,b,c and d from s (and in general
from any longer list of such comma separated pairs).
[...]
In [12]: re.findall(r'(.+)=(.+)', s)
Out[12]: [('a=b, c', 'd')]
I think there are two logically
André andre.robe...@gmail.com writes:
How about the following:
s = 'a=b,c=d'
t = []
for u in s.split(','):
... t.extend(u.split('='))
s = 'a = b = c, d = e'
= ['a ', ' b ', ' c', ' d ', ' e']
Ugh.
-- [mdw]
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