Hi,
I am trying to play around with python and xslt. I have an xml and I want
to transform it to another xml by deleting its one element. The xml is
pasted below:
?xml version=1.0 encoding=UTF-8?
testNode
nodeInfo
nodePeriod nodeTime=6/
nodeBase base=0 /
/nodeInfo
On 2014-07-22, varun bhatnagar varun292...@gmail.com wrote:
I want to strip the space between *nodePeriod* and */nodeInfo*
Can anyone suggest a way out to do that?
Look at str.rstrip() - by default it removes trailing whitespace
including carriage returns.
--
Hi,
Thank you so much for the suggestion.
I tried using the rstrip() function but that did not work. Still getting a
blank space between *nodePeriod* and */nodeInfo *as mentioned in the
above output xml file:
*nodePeriod nodeTime=6/*
* /nodeInfo*
Is there any other way through which
On Tuesday, July 22, 2014 8:53:35 AM UTC-4, varun bhatnagar wrote:
Hi,
Thank you so much for the suggestion.
I tried using the rstrip() function but that did not work. Still getting a
blank space between nodePeriod and /nodeInfo as mentioned in the above
output xml file:
nodePeriod
Hi Tim,
Thanks for replying.
No that is not the output I am looking for.
I just want to scrape out nodeBase base=0 /
But the way I have written my xsl file it is removing it but it is also
leaving a blank space there. I want my output to look like this:
*?xml version=1.0
On 2014-07-22, varun bhatnagar varun292...@gmail.com wrote:
I just want to scrape out nodeBase base=0 /
But the way I have written my xsl file it is removing it but it is also
leaving a blank space there. I want my output to look like this:
This is the part where a certain amount of example
