Ric Da Force [EMAIL PROTECTED] wrote:
I have a string such as 'C1, C2, C3'. Without assuming that each bit of
text is of fixed size, what is the easiest way to change this list so that
it reads:
'C1, C2 and C3' regardless of the length of the string.
import re
data = the first bit, then
Hi,
I have a string such as 'C1, C2, C3'. Without assuming that each bit of
text is of fixed size, what is the easiest way to change this list so that
it reads:
'C1, C2 and C3' regardless of the length of the string.
Regards and sorry for the newbie question,
Ric
--
Ric Da Force wrote:
I have a string such as 'C1, C2, C3'. Without assuming that each bit of
text is of fixed size, what is the easiest way to change this list so that
it reads:
'C1, C2 and C3' regardless of the length of the string.
and.join(C1, C2, C3.rsplit(,, 1))
'C1, C2 and C3'
foo = C1, C2, C3
foo = foo.split(, ) # ['C1', 'C2', 'C3']
foo = , .join(foo[:-1]) + and + foo[-1] # just slicing and
joining it
you can always look for something here:
http://docs.python.org/lib/lib.html
and there:
http://docs.python.org/ref/
if you want to know, what methods an object has,
Ric Da Force said unto the world upon 12/07/2005 02:43:
Hi,
I have a string such as 'C1, C2, C3'. Without assuming that each bit of
text is of fixed size, what is the easiest way to change this list so that
it reads:
'C1, C2 and C3' regardless of the length of the string.
Regards and
If that can help you...
def replaceLastComma(s):
i = s.rindex(,)
return ' and'.join([s[:i], s[i+1:]])
I don't know of ot's better to do a:
' and'.join([s[:i], s[i+1:]])
Or:
''.join([s[:i], ' and', s[i+1:]])
Or:
s[:i] + ' and' + s[i+1]
Maybe the better solution is not in the list...
Cyril
On
