Hi Luke,
you should send this to the scipy user list: [EMAIL PROTECTED]
Bernhard
On May 28, 10:44 am, Luke <[EMAIL PROTECTED]> wrote:
> I'm trying to use Scipy's LU factorization. Here is what I've got:
>
> from numpy import *
> import scipy as Sci
> import scipy.linalg
>
> A=array([[3., -2.,
I'm trying to use Scipy's LU factorization. Here is what I've got:
from numpy import *
import scipy as Sci
import scipy.linalg
A=array([[3., -2., 1., 0., 0.],[-1., 1., 0., 1., 0.],[4., 1., 0., 0.,
1.]])
p,l,u=Sci.linalg.lu(A,permute_l = 0)
now, according to the documentation:
**
