First of all: Thanks for your reply
My use case is the following:
I perform a query to DB and the result of query is this;
>>> print rows
{‘Label’: {'2009:01:30': 9, '2009:01:28': 13, '2009:01:29': 19,
'2009:01:26': 1, '2009:01:27': 3, '2009:01:20': 86, '2009:01:22': 3,
'2009:01:23': 12, '2009:02:
loredana.p...@gmail.com wrote:
> If I want to convert a single date format I can do:
>
> import datetime, dateutil.parser
> d = dateutil.parser.parse('2008-09-26)
> print d.strftime('%A %d, %b %y' )
>
> but if I want convert a long list of time how can do it in the fastest
> way?
> for example:
On Sun, Feb 8, 2009 at 4:46 AM, wrote:
> If I want to convert a single date format I can do:
>
> import datetime, dateutil.parser
> d = dateutil.parser.parse('2008-09-26)
> print d.strftime('%A %d, %b %y' )
>
> but if I want convert a long list of time how can do it in the fastest
> way?
> for ex
If I want to convert a single date format I can do:
import datetime, dateutil.parser
d = dateutil.parser.parse('2008-09-26)
print d.strftime('%A %d, %b %y' )
but if I want convert a long list of time how can do it in the fastest
way?
for example:
from ['2008-09-26’, '2008-09-28’, '2008-09-29’,...
