Shane Lillie wrote:
> I've got a bit of code that looks like this:
>
> for i in xrange(1000):
> # shuffle the doors
> doors = [ 'G', 'C', 'G' ]
> random.shuffle(doors)
>
> # save the doors that have goats (by index)
> goats = [ x for x in range(2) if doors[x] == 'G' ]
>
> but
Shane Lillie wrote:
> I've got a bit of code that looks like this:
>
> for i in xrange(1000):
> # shuffle the doors
> doors = [ 'G', 'C', 'G' ]
> random.shuffle(doors)
>
> # save the doors that have goats (by index)
> goats = [ x for x in range(2) if doors[x] == 'G' ]
>
Usin
Shane Lillie wrote:
> goats = [ x for x in range(2) if doors[x] == 'G' ]
>
> but for some reason the list comprehension is not always returning a
> list with 2 elements in it (sometimes it will be just 1 element).
The problem here is with your usage of the range() function. You provide an
endpoi
I've got a bit of code that looks like this:
for i in xrange(1000):
# shuffle the doors
doors = [ 'G', 'C', 'G' ]
random.shuffle(doors)
# save the doors that have goats (by index)
goats = [ x for x in range(2) if doors[x] == 'G' ]
but for some reason the list comprehension is
