I have the following code:
from __future__ import division, print_function
import subprocess
p = subprocess.Popen('ls -l', shell = True, stdout = subprocess.PIPE)
for line in iter(p.stdout.readline, ''):
print(line.rstrip().decode('utf-8'))
p =
On 19 May 2015 at 13:24, Cecil Westerhof ce...@decebal.nl wrote:
I have the following code:
from __future__ import division, print_function
import subprocess
p = subprocess.Popen('ls -l', shell = True, stdout = subprocess.PIPE)
for line in iter(p.stdout.readline, ''):
Op Tuesday 19 May 2015 15:16 CEST schreef Oscar Benjamin:
On 19 May 2015 at 13:24, Cecil Westerhof ce...@decebal.nl wrote:
I have the following code:
from __future__ import division, print_function
import subprocess
p = subprocess.Popen('ls -l', shell = True, stdout =
subprocess.PIPE)
Am 19.05.2015 um 15:16 schrieb Oscar Benjamin:
However the normal way to do this is to iterate over stdout directly:
Depends. There may be differences when it comes to buffering etc...
Thomas
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Op Tuesday 19 May 2015 17:49 CEST schreef Ian Kelly:
On Tue, May 19, 2015 at 8:44 AM, Cecil Westerhof ce...@decebal.nl wrote:
I looked at the documentation. Is it necessary to do a:
p.wait()
afterwards?
It's good practice to clean up zombie processes by waiting on them,
but they will also
On Wed, May 20, 2015 at 2:39 AM, Cecil Westerhof ce...@decebal.nl wrote:
By the way, what also works is:
p = None
But it was just a try in ipython3. I would never do this in real code.
I was just curious if this would be handled correctly and it is. :-)
That _may_ work, but it depends on
On Tue, May 19, 2015 at 8:44 AM, Cecil Westerhof ce...@decebal.nl wrote:
I looked at the documentation. Is it necessary to do a:
p.wait()
afterwards?
It's good practice to clean up zombie processes by waiting on them,
but they will also get cleaned up when your script exits.
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