Hello
Python's doc says about loop.call_soon(callback, *arg):
Arrange for a callback to be called as soon as possible. The callback is called
after call_soon() returns, when control returns to the event loop.
But it doesn't seem to be true; see this program:
import asyncio
async def task_fu
On Tue, Nov 28, 2017 at 8:30 AM, ast wrote:
> Hello
>
> Python's doc says about loop.call_soon(callback, *arg):
>
> Arrange for a callback to be called as soon as possible. The callback is
> called after call_soon() returns, when control returns to the event loop.
>
> But it doesn't seem to be tru
On 11/28/2017 11:02 AM, Ian Kelly wrote:
On Tue, Nov 28, 2017 at 8:30 AM, ast wrote:
Hello
Python's doc says about loop.call_soon(callback, *arg):
Arrange for a callback to be called as soon as possible. The callback is
called after call_soon() returns, when control returns to the event loop.
