Antoon Pardon wrote:
So and if I have code like this:
f = lamda x:x
for g in some_iter:
f = compose(g,f)
Do you still think that one should use a named function in this case?
Yes. If you really don't like taking two lines, Python still allows you
to write this as:
def f(x): return x
Op 2005-02-18, Steven Bethard schreef <[EMAIL PROTECTED]>:
> Paddy McCarthy wrote:
>> x=lambda : A < B
>> y=lambda : C+6 >= 7
>>
> [snip]
>>
>> Z=lambda : (A=7)
>
> See "Inappropriate use of Lambda" in
> http://www.python.org/moin/DubiousPython
>
> Perhaps your real example is different, but notice
Steve,
Thanks for the info but I do know about that..
What I am doing is taking a set of inputted functions that don't
take arguments and programmatically analysing them and
combining them to create new functions that are further analysed.
During testing I keep the numbers low, and am only dealing
Paddy McCarthy wrote:
x=lambda : A < B
y=lambda : C+6 >= 7
[snip]
Z=lambda : (A=7)
See "Inappropriate use of Lambda" in
http://www.python.org/moin/DubiousPython
Perhaps your real example is different, but notice that
= lambda :
is equivalent to
def ():
return
except that the latt
[EMAIL PROTECTED] wrote:
> I actually have a set of lambdas so my use will be more like:
A set of lambdas gains you nothing.
>>> (lambda: a > 0) in set([lambda: a > 0])
False
is probably not what you expected. So you might want to go back to strings
containing expressions. Anyway, here is a way
Fredrik Lundh wrote:
> Paddy McCarthy wrote:
>
> > #If given:two or more lambda equations
> > x=lambda : A < B
> > y=lambda : C+6 >= 7
> >
> > How do I create another lambda expression Z equivalent to
> >
> > Z=lambda : (A=7)
> >
> > # i.e. the anding together of the originals, but without
referenc
Paddy McCarthy wrote:
> #If given:two or more lambda equations
> x=lambda : A < B
> y=lambda : C+6 >= 7
>
> How do I create another lambda expression Z equivalent to
>
> Z=lambda : (A=7)
>
> # i.e. the anding together of the originals, but without referencing
> # globals x and y as they are artifi
Hi,
I am trying to use eval as little as possible but solve this problem.
#If given:two or more lambda equations
x=lambda : A < B
y=lambda : C+6 >= 7
...
How do I create another lambda expression Z equivalent to
Z=lambda : (A=7)
# i.e. the anding together of the originals, but without referenc
