the complementary subset to y z=[2,3,5,6,8,9] ?
>
> >> The reason I ask is because I have a generator function that generates
> >> a list of tuples and I would like to divide this list into
> >> complementary lists.
>
> > z = [u for u in x if u not in y]
>
the complementary subset to y z=[2,3,5,6,8,9] ?
>
> >> The reason I ask is because I have a generator function that generates
> >> a list of tuples and I would like to divide this list into
> >> complementary lists.
>
> > z = [u for u in x if u not in y]
>
reason I ask is because I have a generator function that generates
>> a list of tuples and I would like to divide this list into
>> complementary lists.
>
> z = [u for u in x if u not in y]
>
> or
>
> z = [u for u in x if u not in set(y)]
The above will evaluate set(y
Ross writes:
> If I have a list x = [1,2,3,4,5,6,7,8,9] and another list that is a
> subset of x: y = [1,4,7] , is there a quick way that I could return
> the complementary subset to y z=[2,3,5,6,8,9] ?
>>> x = [1,2,3,4,5,6,7,8,9]
>>> y = [1,4,7]
>>> print sorted(set(x)-set(y))
r function that generates
> a list of tuples and I would like to divide this list into
> complementary lists.
>>> s = set([1,2,3,4,5,6,7,8,9])
>>> s.difference(set([1,4,7]))
set([2, 3, 5, 6, 8, 9])
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r function that generates
> a list of tuples and I would like to divide this list into
> complementary lists.
z = [u for u in x if u not in y]
or
z = [u for u in x if u not in set(y)]
Since you are dealing with tuples and a natural order might not be
that relevant you can also set objects in th
divide this list into
complementary lists.
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